To solve this problem it is necessary to apply the equations related to the law of Maus.
By the law of Maus we know that

Where,
= Intesity of incident light
I = Intensity of polarized light
With our values we have that
6V/m

Then


Therefore the maximum value of the transmitted E vector is 3V/m
How deep and how much an object weighs........................................
Answer:
The velocity of the stone is 2.57 m/s.
Explanation:
Given that
Height = 0.337 m
We need to calculate the velocity of the stone
Using equation of motion

Where, v = velocity of stone
u = initial velocity
g = acceleration due to gravity
h = height
Put the value into the formula



Hence, The velocity of the stone is 2.57 m/s.
Answer:
0.71121 km/s
Explanation:
= Velocity of planet initially = 54 km/s
= Distance from star = 0.54 AU
= Final velocity of planet
= Final distance from star = 41 AU
As the angular momentum of the system is conserved

When the exoplanet is at its farthest distance from the star the speed is 0.71121 km/s.