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Gre4nikov [31]
2 years ago
13

What may result when the energy that builds up at plate boundaries is released because the plates suddenly overcome the force of

friction?
volcano


hot spot


earthquake


trench
Physics
2 answers:
Dahasolnce [82]2 years ago
7 0
What may result when the energy that builds up at plate boundaries is released because the plates suddenly overcome the force of friction?


earthquake


Arlecino [84]2 years ago
4 0
It has to be Earthquake
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Stronger and harder than either of the pure metals

Explanation:

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3 years ago
An eagle is flying horizontally at a speed of 3.10 m/s when the fish in her talons wiggles loose and falls into the lake 6.10 m
Alinara [238K]

Answer:

10.93m/s with the assumption that the water in the lake is still (the water has a speed of zero)

Explanation:

The velocity of the fish relative to the water when it hits the water surface is equal to the resultant velocity between the fish and the water when it hits it.

The fish drops on the water surface vertically with a vertical velocity v. Nothing was said about the velocity of the water, hence we can safely assume that the velocity if the water in the lake is zero, meaning that it is still. Therefore the relative velocity becomes equal to the velocity v with which the fish strikes the water surface.

We use the first equation of motion for a free-falling body to obtain v as follows;

v = u + gt....................(1)

where g is acceleration due to gravity taken as 9.8m/s/s

It should also be noted that the horizontal and vertical components of the motion are independent of each other, hence we take u = 0 as the fish falls vertically.

To obtain t, we use the second equation of motion as stated;

h=ut+gt^2/2.................(2)

Given; h = 6.10m.

since u = 0 for the vertical motion;  equation (2) can be written as follows;

h=\frac{1}{2}gt^2............(3)

substituting;

6.1=\frac{1}{2}*9.8*t^2\\6.1=4.9t^2\\hence\\t^2=6.1/4.9\\t^2=1.24\\t=\sqrt{1.24}=1.12s

Putting this value of t in equation (1) we obtain the following;

v = 0 + 9.8*1.12

v = 10.93m/s

5 0
3 years ago
A fast pitch softball player does a "windmill" pitch moving her hand through a vertical circular arc to pitch a ball at 70mph. T
uysha [10]

Answer:

Explanation:

The hand throwing ball moves on a circular path having radius r = .55 m

mass of ball m = .19 kg

velocity v = 70 mph

= 70 x 1600 / 60 x 60

= 31.11 m /s

centripetal force

= mv² / r

= .19 x 31.11² / .55

= 334.34 N

8 0
3 years ago
A stone is dropped from the top a 45m hign building how fast will it moving when it reaches the ground? Ande what will its veloc
posledela

Answer:

29.7 m/s fast, velocity is 29.7 m/s

Explanation:

Applying,

v² = u²+2gs...................... Equation 1

Where v = final velocity, u = initial velocity, g = acceleration due to gravity, s = distance.

Given: u = 0 m/s (dropped from height), s = 45 m

Constant: g = 9.8 m/s²

Substitute these values into equation 1

v² = 0²+2×9.8×45

v² = 882

v = √(882)

v = 29.7 m/s.

Hence the stone will be moving 29.7 m/s fast and the velocity is also 29.7 m/s

7 0
3 years ago
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