Answer:
The approximate distance is 15416 miles....
Step-by-step explanation:
We have given:
A satellite is 19,000 miles from the horizon of earth.
The radius is 4,000 miles.
Lets say that BC =x
AO = OB = 4,000 miles
AC = 19,000 miles
The tangent from the external point forms right angle with the radius of the circle.
So in ΔABC
(OC)² = (AC)²+(OA)²
where OC = x+4000
AC = 19,000
OA = 4000
Therefore,
(x+4000)² = (19,000)² +(4,000)²
Take square root at both sides:
√(x+4000)² = √(19,000)² +(4,000)²
x+4000 =√361000000+16000000
x+4000 = √377000000
x+4000 = 19416.48
x= 19416.48 - 4000
x = 15416.48
Therefore the approximate distance is 15416 miles....
You can do substitution 2x-2=x^2 -x -6; isolate all terms on one side 0= x^2 -x-2x -6+2; combine like terms x^2 -3x -4=0; factor the quadratic (x-4)(x+1)=0; each term is zero x-4=0 so x=4 and x+1=0 so x=-1. Now, y=2•4-2=6 and y=2•(-1) -2= -4 ; solutions for the system are ( 4,6) and ( -1, -4)
Since there are 12 inches in 1 foot you have to divide 84 by 12
84 divided by 12 is 7
So, there are 7 feet in 84 inches
Answer:
The answer to your question is 7x2+5x
Step-by-step explanation:
Step-by-step explanation:
it's easy to prove in any right triangle with a 30° angle, the side opposite to that angle is half the hypotenuse. CA (1/2)BC, CA/BC=1/2
