Which of the following is true regarding electrons?

(Exercise 5.2.14 modified) A common method used to produce bleach (sodium hypochlorite) is by the reaction Cl2 + 2NaOH  NaCl +

Oksana_A [137]

Answer:

Chlorine is limiting reactant

Explanation:

Based on the reaction:

Cl₂ + 2NaOH → NaClO + NaCl + H₂O

<em>1 mole of chlorine reacts with 2 moles of NaOH</em>

<em />

To find limiting reactant, we need to determine the moles of the reactants:

<em />

<em>Moles Cl₂ -Molar mass: 70.9g/mol-:</em>

800lb Cl₂ * (453.6g / 1lb) * (1mol / 70.90g) =

5118 moles Cl₂

<em>Moles NaOH -Molar mass: 40g/mol-:</em>

1200lb NaOH * (453.6g / 1lb) * (1mol / 40g) =

13608 moles NaOH

For a complete reaction of 13608 moles of NaOH you need:

13608 moles NaOH * (1mol Cl₂ / 2 moles NaOH) = 6804 moles of Cl₂

As the solution contains just 5118 moles of chlorine,

<h3>Chlorine is limiting reactant</h3>

8 0

3 years ago

Calculate the molar concentration of the Br⁻ ions in 0.51 M MgBr2(aq), assuming that the dissolved substance dissociates complet

Y_Kistochka [10]

MgBr2(aq) is an ionic compound which will have the releasing of 2 Br⁻ ions ions in water for every molecule of MgBr2 that dissolves.
MgBr2(s) --> Mg+(aq) + 2 Br⁻(aq)
[Br⁻] = 0.51 mol MgBr2/1L × 2 mol Br⁻ / 1 mol MgBr2 = 1.0 M
The answer to this question is [Br⁻] = 1.0 M

6 0

3 years ago

An alkane with the formula C6H14 can be prepared by hydrogenation of either of two precursor alkenes having the formula C6H12.

ankoles [38]

Two precursor alkenes

H₃C CH₃
I I
H₂C=C-CH-CH₃ 2,3-dimethyl-1-butene

H₃C   CH₃
I   I
H₃C-CH=CH-CH₃ 2,3-dimethyl-2-butene

alkane

H₃C CH₃
  I I
H₃C-CH-CH-CH₃ 2,3-dimethylbutane

H₃C  CH₃ H₃C CH₃
I   I I I
H₂C=C-CH-CH₃ + H₂ → H₃C-CH-CH-CH₃

H₃C CH₃ H₃C   CH₃
I    I     I I
H₂C-C=CH-CH₃ + H₂ → H₃C-CH-CH-CH₃

6 0

3 years ago

Read 2 more answers

Please help on this question

natulia [17]

Send a more clearer picture...
But I will tell u the system of the Hadley cells---
METEOROLOGY
a large-scale atmospheric convection cell in which air rises at the equator and sinks at medium latitudes, typically about 30° north or south.

7 0

3 years ago

State the oxidation number of S in <br><img src="https://tex.z-dn.net/?f=H_%7B2%7DSO_%7B3%7D" id="TexFormula1" title="H_{2}SO_{3

Nezavi [6.7K]

Taking into account the definition of oxidation number, the oxidation numbers of S in H₂SO₃ is 4.

<h3>Definition of oxidation number</h3>

The oxidation number is the charge that an atom has; is an integer that represents the number of electrons an atom puts into play when it forms a given compound.

In other words, the oxidation number of an element is a value that indicates the number of electrons that element gains or loses when it combines with another.

<h3>Oxidation number determination</h3>

To determine the oxidation state of different elements it is necessary to know that:

The oxidation number of hydrogen in a compound is +1, except in metal hydrides, where is –1.
The oxidation number of oxygen in a compound is –2, except in peroxides, where it is –1.

On the other side, the sum of the oxidation numbers of the existing elements in a chemical formula must add up to zero.

Then, considering the oxidation numbers of each element, multiplying it by the number of existing elements in the chemical formula and adding it and equaling it to zero, the value of the missing oxidation number can be obtained.

<h3>Oxidation numbers of S</h3>

In this case, the oxidation numbers of S in H₂SO₃ is calculated as:

2× (+1) + oxidation numbers of S + 3×(-2)= 0

2 + oxidation numbers of S -6= 0

oxidation numbers of S -4= 0

<u><em>oxidation numbers of S= 4</em></u>

Finally, the oxidation numbers of S in H₂SO₃ is 4.

Learn more about the oxidation number:

brainly.com/question/8990767

brainly.com/question/6498977

5 0

2 years ago

Read 2 more answers