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3 years ago

If a bar of motilium cost .0.2 dollars how much will 200 bars cost

Chemistry

1 answer:

lorasvet [3.4K]3 years ago

3 0

Answer: 40

Explanation: 0.2 x 200

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I need help with this pls

coldgirl [10]

Answer:

C Is The Correct Answer Because The Deeper The Rock Is The Older It Is So The Top Is The Youngest And The Bottem Is The Oldest

8 0

3 years ago

For the reactions system 2H2(g) + S2(g) 2H2S(g), a 1.00 liter vessel is found to contain 0.50 moles of H2, 0.020 moles of S2, an

Mnenie [13.5K]

Answer: 1) $2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)$

Equilibrium constant is defined as the ratio of the product of concentration of products to the product of concentration of reactants each term raised to their stochiometric coefficients.

$K_{eq}=\frac{[H_2S]^2}{H_2]^2\times [S_2]}$

where [] = concentration in Molarity= $\frac{moles}{\text {Volume in L}}$

Thus $[H_2S]=\frac{68.5}{1.0}=68.5M$

$[H_2]=\frac{0.50}{1.0}=0.50M$

$[S_2]=\frac{0.020}{1.0}=0.020M$

$K_{eq}=\frac{[68.5]^2}{0.50]^2\times [0.020]}=938450$

As the value of K is greater than 1, the reaction is product favored.

2) $N_2O_4(g)\rightleftharpoons 2NO_2(g)$

$K_{eq}=\frac{[NO_2]^2}{[N_2O_4]}$

$K_{eq}=\frac{[0.500]^2}{[0.0250]}=10$

3) $N_2+3H_2\rightleftharpoons 2NH_3$

$K_{eq}=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}$

4) Reactions which do not continue to completion are called equilibrium reactions as the rate of forward reaction is equal to the rate of backward direction.

3 0

3 years ago

Read 2 more answers

Which diagram represents this molecule?

zepelin [54]

Answer:

Explanation:

The molecule has 8 carbon atoms joined by 7 C-C bonds.

The first two diagrams show 6 carbon atoms, not 8.

The last two diagrams show line segments representing C-C bonds. Only choice C shows 7 such segments.

The appropriate choice is C.

7 0

3 years ago

A 9.000L tank at 27.0°C is filled with 5.29g of sulfur tetrafluoride gas and 15.6g of carbon dioxide gas. You can assume both ga

Colt1911 [192]

Answer:

Mole fraction SF₄: 0,121

Mole fraction CO₂: 0,879

Partial pressure SF₄: 0,134 atm

Partial pressure CO₂: 0,968 atm

Total pressure: 1,102 atm

Explanation:

The moles of sulfur tetrafluoride gas and carbon dioxide gas are:

5,29g SF₄× $\frac{1mol}{108,07g}$ = 0,0489 moles SF₄

15,6 CO₂× $\frac{1mol}{44,01g}$ = 0,354 moles CO₂

Mole fraction SF₄:

$X_{SF_{4}} = \frac{0,0489mol}{0,0489+0,354}$ = 0,121

Mole fraction CO₂:

$X_{CO_{2}} = \frac{0,354mol}{0,0489+0,354}$ = 0,879

It is possible to obtain partial pressure of both gases with moles of each gas using:

P = nRT/V

Where n are respective moles, R is gas constant (0,082atmL/molK), T is teemperature (27°C=300,15K), V is volume (9,0000L)

Replacing:

Partial pressure SF₄: 0,134atm

Partial pressure CO₂: 0,968atm

Now, the sum of the partial pressures is the total pressure in the tank, that means:

Total pressure: 0,134atm + 0,968atm = 1,102atm

I hope it helps!

6 0

3 years ago

Dimethyl sulfoxide [(ch3)2so], also called dmso, is an important solvent that penetrates the skin, enabling it to be used as a t

Bas_tet [7]

The molecular formula of dimethyl sulfoxide is $(CH_{3})_{2}SO$ . Molar mass of dimethyl sulfoxide is 78.13 g/mol. Calculate number of moles as follows: