If E=1/2Av^2+Bmx find the dimensions of A and B(Where E is energy,v,m and x are velocity,mass and distance respectively)
1 answer:
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(a) 34.6 N
To solve the problem, we have to analyze the forces acting along the horizontal direction.
We have:
- Forward: the component of the pull parallel to the ground, which is
where
F is the magnitude of the pull
is the angle
- Backward: the force of friction, which is
So, the equation of motion is
where
m = 20 kg is the mass of the wagon
a is the acceleration
In this part, the wagon is moving at constant speed, so a =0 and the equation becomes
Therefore, we can find the pulling force:
(b) 43.9 N
In this case, the acceleration is
So, the equation of motion in this case is
So this time we have to take into account the term (ma).
Using the same data as before:
m = 20 kg
We find the new magnitude of F:
The equations to find the acceleration are the suvat equations:
Explanation:
The acceleration of an object is the rate if change in velocity of the object. It is calculated as
where
v is the final velocity of the object
u is the initial velocity
t is the time elapsed
For an object moving in a straight line at constant acceleration, there are several equations that can be used to find the acceleration: they are called suvat equations. They are the following:
where
u is the initial velocity
v is the final velocity
t is the time
s is the distance covered
a is the acceleration
Therefore, any of the above equations can be used to calculate the acceleration.
Learn more about acceleration:
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