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3 years ago

8

Object A attracts object B with a gravitational force of 10 newtons from a given distance. If the distance between the two objec

ts is doubled.
what is the new force of attraction between them?
ОА
2.5 newtons
ОВ.
5 newtons
OC 20 newtons
OD.
100 newtons

1 answer:

timurjin [86]3 years ago

7 0

Answer:b

Explanation:the greater the distance the less power.

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Luz, who is skydiving, is traveling at terminal velocity with her body parallel to the ground. She then changes her body positio

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Answer:

Option C - she will speed up because air resistance has reduced and be less than gravity

Explanation:

We are told that Luz is skydiving with terminal velocity and her body parallel to the ground. Now, at this point she will be experiencing a gravitational force acting downwards, and also air resistance as a result of the drag force on her body

Since the downward gravitational force on Luz is constant, she will fall with a net force of;

F_net = F_g - F_d

where;

F_net is the net force on Luz acting downwards

F_g is the gravitational force on Luz

F_d is the drag force on Luz

The drag force on her body is proportional to the surface area of attack.

We are now told that Luz changes her body position to feet first toward the ground. This means that the surface area of attack is reduced because the feet will consume less space than the frontal part of her body. Thus, the drag force will be lesser then before she changed her body position due to reduced air resistance on her body.

Now, from earlier, we saw that;

F_net = F_g - F_d

So, the lesser F_d is, the higher F_net becomes.

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3 years ago

If the position of a particle on the x-axis at time t is âˆ’5t2, then the average velocity of the particle for 0 â‰¤ t â‰¤ 3 is

Drupady [299]

Answer:

v = 15 m / s

Explanation:

In this exercise we are given the position function

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$v= \frac{v_{f} - v_{o} }{t_{f} - t_{o} }$

let's look for the displacements

t = 0 x₀ = 0 m

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x_{f} = 45 m

we substitute

$v = \frac{45 -0}{3 - 0}$

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3 years ago

A car travels 2,000 mi at a<br> constant speed of 70 mi/hr.<br> How long did the trip take?

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Answer:

<h2>28.57 hours</h2>

Explanation:

The time taken can be found by using the formula

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d is the distance

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From the question we have

$t = \frac{2000}{70} = \frac{200}{7} \\ = 28.571428 ...$

We have the final answer as

<h3>28.57 hours</h3>

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3 years ago

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Answer:

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4 years ago