To solve this problem we will apply the concepts related to the conservation of momentum. This can be defined as the product between the mass and the velocity of each object, and by conservation it will be understood that the amount of the initial momentum is equal to the amount of the final momentum. By the law of conservation of momentum,

$m_1u_1+m_2u_2 = m_1v_1+m_2v_2$

Here,

$m_1$ = Mass of Basketball

$m_2$ = Mass of Tennis ball

$u_1$ = Initial velocity of Basketball

$u_2$ = Initial Velocity of Tennis ball

$v_1$ = Final velocity of Basketball

$v_2$ = Final velocity of the tennis ball

Replacing,

$(0.8)(0.5)+(0.1)(-5.0)=(0.8)(0.3)+(0.1)v_2$

Solving for the final velocity of the tennis ball

$v_2 = 11m/s^2$

Therefore the velocity of the tennis ball after collision is 11 m/s

3 0

3 years ago

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A race car starting from rest accelerates uniformly at a rate of 3.90 m/s^2 what is the cars speed after it has traveled 200 m.

snow_tiger [21]

The formula for accelerational displacement is at^2/2, so we know that 3.9t^2/2 = 200, or 3.9t^2 = 400. t = $\sqrt{400/3.9} \approx 10.12739367$ , at = v, so $3.9 * 10.12739367 \approx 39.5 m/s$