1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Soloha48 [4]
3 years ago
8

An exploration submarine should be able to descend 1200 m down in the ocean. If the ocean density is 1020 kg/m3, what is the max

imum pressure on the submarine hull?
Physics
1 answer:
motikmotik3 years ago
8 0

Answer:

11995200 N/m²

Explanation:

Pressure: The is the ratio of force to the surface area in contact. The S.I unit of pressure is N/m².

Generally pressure in fluid can be expressed as

P = ρgh......................... Equation 1

Where P = maximum pressure on the submarine hull, ρ = Density of ocean, h = depth of ocean, g = acceleration due to gravity.

Given: h = 1200 m, ρ = 1020 kg/m³

Constant: g = 9.8 m/s²

Substitute into equation 1

P = 1200(1020)(9.8)

P = 11995200 N/m²

Hence the maximum pressure on the submarine hull = 11995200 N/m²

You might be interested in
Why does gravity on Earth have a stronger attraction with you than the sun has with you? Plsssssss help I really need this rn
n200080 [17]

Answer:

Although the Earth has a lesser mass than the Sun, it is far closer to you, allowing for a stronger pull.

Explanation:

5 0
3 years ago
What did Thomson’s and Rutherford’s experiments have in common? They both used charged particles in their experiments. They both
Triss [41]

Answer:

Both Thomson and Rutherford used charged particles in their experiments.

Explanation:

6 0
3 years ago
Read 2 more answers
The International Space Station has a mass of 1.8 × 105 kg. A 70.0-kg astronaut inside the station pushes off one wall of the st
Aleonysh [2.5K]

Answer:

a = 5.83 \times 10^{-4} m/s^2

Explanation:

Since the system is in international space station

so here we can say that net force on the system is zero here

so Force by the astronaut on the space station = Force due to space station on boy

so here we know that

mass of boy = 70 kg

acceleration of boy = 1.50 m/s^2

now we know that

F = ma

F = 70(1.50) = 105 N

now for the space station will be same as above force

F = ma

105 = 1.8 \times 10^5 (a)

a = \frac{105}{1.8 \times 10^5}

a = 5.83 \times 10^{-4} m/s^2

3 0
3 years ago
An astronaut has a mass of 74.0 kg. 1) how much would the astronaut weigh on mars where surface gravity is 38.0% of that on eart
NeX [460]
274.614N or 61.736lbs
3 0
3 years ago
Read 2 more answers
What force is required to accelerate a body with a mass of 15 kilograms at a rate of 8 m/s²?
mihalych1998 [28]

Newton's Second law of motion: 

                  Force = (mass) x (acceleration)

                  Force = (15kg) x (8m/s²) = 120 kg-m/s² = 120 newtons
6 0
3 years ago
Read 2 more answers
Other questions:
  • Two rocks are tied to massless strings and whirled in nearly horizontal circles so that the time to travel around the circle onc
    9·1 answer
  • Reducing waste and recycling things are ways to conserve energy. True false
    5·2 answers
  • Wave A has a wavelength of 2 meters and a frequency of 1.5 Hz . calculate the wave's speed
    9·1 answer
  • A child, who is 45 m from the bank of a river, is being carried helplessly downstream by the river's swift current of 1.0 m/s. A
    12·1 answer
  • Renewable resources can be
    14·1 answer
  • Turning the barrel of a 50-mm-focal-length lens on a manual-focus camera moves the lens closer to or farther from the sensor to
    5·1 answer
  • The ________ is the maximum value or strength of the signal over time; typically this value is measured in volts.
    10·1 answer
  • An average human has a heart rate of 70 beats per minute. If someone's heart
    10·2 answers
  • Why do scientists ask questions?
    14·2 answers
  • Use this free body diagram to help you find the magnitude of the force needed to keep this block in static equilibrium.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!