Answer:
The decay constant is 1.21×10^-4/year
Explanation:
Decay constant = 0.693/half-life
Half-life = 5730 years
Decay constant = 0.693/5730 years = 1.21×10^-4/year
Answer:
a = 4.96 m/s²
Explanation:
Given,
The mass of the box, m = 51 Kg
The magnitude of the applied force, Fₐ = 485 N
The friction force on the box, Fₓ = 232 N
The net force acting on the box is,
F = Fₐ - Fₓ
Substituting the given values in the above equation
F = 485 - 232
= 253 N
The acceleration of the crate is given by
a = F/m
= 253 / 51
= 4.96 m/s²
Hence, the acceleration of the crate is, a = 4.96 m/s²
Answer:
b. the planets are marble-size or smaller and the nearest stars are thousands of miles away
Explanation:
The correct answer for the question is option b because if the distance between sun and Pluto is any scale is made equivalent to a walking distance of some minutes then the size of planets will be equivalent to the size of marbles and the nearest stars that is present in Alpha centauri triple star system(4.5 light years away) will be approximately thousands of miles away from us.
Answer:
the answer will be C. 4 degrees C
Explanation:
you subtract base meters from peak meters to get 4 meters; then Multiply 6.5 by 4.
Then subtract that total from 30 degrees C
***as altitude increases, temperature decreases***
Answer:
D. 2^(3/2)
Explanation:
Given that
T² = A³
Let the mean distance between the sun and planet Y be x
Therefore,
T(Y)² = x³
T(Y) = x^(3/2)
Let the mean distance between the sun and planet X be x/2
Therefore,
T(Y)² = (x/2)³
T(Y) = (x/2)^(3/2)
The factor of increase from planet X to planet Y is:
T(Y) / T(X) = x^(3/2) / (x/2)^(3/2)
T(Y) / T(X) = (2)^(3/2)
