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3 years ago

14

The first side of a triangle is 3 inches shorter than the second side, and 2 inches longer than the third side. How long is each

side, if the triangle has a perimeter of 28 inches?

1 answer:

ziro4ka [17]3 years ago

7 0

Answer:

the length of the first side of the triangle is $\frac{28}{3}\ in$

the length of the second side of the triangle is $\frac{37}{3}\ in$

the length of the third side of the triangle is $\frac{19}{3}\ in$

Step-by-step explanation:

Let

x-----> the length of the first side of a triangle

y----> the length of the second side of a triangle

z---> the length of the third side of a triangle

we know that

$x=y-3$

$y=x+3$ -----> equation A

$x=z+3$

$z=x-3$ -----> equation B

The perimeter of the triangle is equal to

$P=x+y+z$

$P=28\ in$

so

$28=x+y+z$ -----> equation C

substitute equation A and equation B in equation C

$28=x+(x+3)+(x-3)$

solve for x

$28=3x$

$x=\frac{28}{3}\ in$

Find the value of each side

the first side of a triangle is x

$x=\frac{28}{3}\ in$

the second side of a triangle is y

$y=\frac{28}{3}+3=\frac{37}{3}\ in$

the third side of a triangle is z

$z=\frac{28}{3}-3=\frac{19}{3}\ in$

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