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Alex73 [517]
3 years ago
14

The first side of a triangle is 3 inches shorter than the second side, and 2 inches longer than the third side. How long is each

side, if the triangle has a perimeter of 28 inches?
Mathematics
1 answer:
ziro4ka [17]3 years ago
7 0

Answer:

the length of the first side of the triangle is \frac{28}{3}\ in

the length of the second side of the triangle is \frac{37}{3}\ in

the length of the third side of the triangle is \frac{19}{3}\ in

Step-by-step explanation:

Let

x-----> the length of the first side of a triangle

y----> the length of the second side of a triangle

z---> the length of the third side of a triangle

we know that

x=y-3

y=x+3 -----> equation A

x=z+3

z=x-3  -----> equation B

The perimeter of the triangle is equal to

P=x+y+z

P=28\ in

so

28=x+y+z -----> equation C

substitute equation A and equation B in equation C

28=x+(x+3)+(x-3)

solve for x

28=3x

x=\frac{28}{3}\ in

Find the value of each side

the first side of a triangle is x

x=\frac{28}{3}\ in

the second side of a triangle is y

y=\frac{28}{3}+3=\frac{37}{3}\ in

the third side of a triangle is z

z=\frac{28}{3}-3=\frac{19}{3}\ in

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