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Anvisha [2.4K]
3 years ago
11

Line GH contains points G(–2, 6) and H(5, –3). Given the points, what is the slope of the line ?.

Mathematics
2 answers:
IRINA_888 [86]3 years ago
6 0
The slope is m = rise/run
m = ( -3 - 6 ) / ( 5 - ( -2 )) = -9 / ( 5 + 2 ) = - 9/7
Answer: the slope of the line is -9/7.
user100 [1]3 years ago
4 0
The term to find the slope is Y2-Y1/X2-X2. So it becomes -3-6/5-(-2) which translates to -3-6/5+2 and YOUR FINAL ANSWER IS: -9/7.
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What is the sum of the measures of the interior angles formed by the boundary of this team pennant?
Debora [2.8K]
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3 0
2 years ago
Read 2 more answers
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
2 years ago
What is the value of x to the nearest tenth? <br> <br><br>       A. 9.7   B. 8.1   C. 5.9   D. 7.9
8090 [49]
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7 0
3 years ago
Read 2 more answers
Write in simplest form. 2^9÷2^3 PLEASE HELP
Paha777 [63]

Answer:

27

Step-by-step explanation:

2x9/2x3=27

7 0
3 years ago
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Add all of them up and then divide by 10.
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2 years ago
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