Solve for the following variable: y = mx b, solve for x

If you have 30$ and you need to find 8%, and add to 30$ then find 15% of that, and what’s your total?

stira [4]

Answer:

Our total amount value is $4.86.

Step-by-step explanation:

The total amount given is $30.

Now 8 % of $30 = $\frac{8}{100} \times 30 = 2.4$

or, 8% of $30 = $2.4

Now adding $30 and $2.4,

$ 30 + $2.4 = $32.4

Finding 15% of the total $32.4,

we get $\frac{15}{100} \times 32.4 = 4.86$

or, 15% of $32.4 = $4.86

hence, our total amount value is $4.86.

5 0

3 years ago

Consider the following sets of sample data: A: $29,400, $30,900, $21,000, $33,200, $21,300, $24,600, $29,500, $22,500, $35,200,

Lana71 [14]

Answer:

CV for A = 21.8%

CV for B = 15.5%

Step-by-step explanation:

The formula for coefficient of variation is:

CV = Standard Deviation / Mean

So,

For A:

Mean = Sum/No. of items

= 391300/14

=$27950

and

SD = $6085.31

CV for A = 6085.31/27950 * 100

=21.77%

Rounding off to one decimal

CV for A = 21.8%

For B:

Mean = Sum/No. of items

= 43.58/11

=3.96

and

SD = 0.615

CV for B = 0.615/3.96 * 100

=15.53%

=15.5% ..

6 0

3 years ago

Simplify:<br> 2(xy - 7) = [?]<br> x = -1 and y = 3

fiasKO [112]

Answer:2(xy-7)= -20

Step-by-step explanation:

Plug in -1 for x and 3 for 3, as the question says that x and y represent those values.

2(xy-7) = ?

2((-1)(3) - 7) = ?

2(-3-7)=?

2(-10)

-20

2(xy - 7) = -20

5 0

3 years ago

A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measurin

Ratling [72]

Answer:

The standard deviation of weight for this species of cockroaches is 4.62.

Step-by-step explanation:

Given : A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measuring the weights of many of these cockroaches, a lab assistant reports that 14% of the cockroaches weigh more than 55 grams.

To find : What is the approximate standard deviation of weight for this species of cockroaches?

Solution :

We have given,

Mean $\mu=50$