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Marianna [84]
3 years ago
4

Let sets A space equals open curly brackets 1 comma space 2 comma space 3 comma space 4 close curly brackets and B space equals

space open curly brackets 1 comma space left curly bracket 3 right curly bracket comma space 1 comma space left curly bracket 1 comma space 3 right curly bracket comma space left curly bracket 3 comma space 3 comma space 1 right curly bracket close curly brackets. Choose the contents of A space union space B and A space cross times space B in roster notation (removing duplicates).
Mathematics
1 answer:
blagie [28]3 years ago
5 0

Answer:

(i)A \cup B ={1,2,3,4,{3},{1,3}}

(ii)A X B ={(1,1), (1,{3}),(1,{1,3}),(2,1), (2,{3}),(2,{1,3}),(3,1), (3,{3}),(3,{1,3}),(4,1), (4,{3}),(4,{1,3})}

Step-By-Step Explanation:

A={1,2,3,4}

B={1,{3},1,{1,3},{3,3,1}}

Removing Duplicates: B={1,{3},{1,3}}

Definition : Given two non-empty sets A and B, the set of all ordered pairs (x, y), where x ∈ A and y ∈ B is called Cartesian product of A and B; symbolically, we write A × B = {(x, y) |  x ∈ A and y ∈ B}  

(i)A \cup B ={1,2,3,4,{3},{1,3}}

(ii)A X B ={(1,1), (1,{3}),(1,{1,3}),(2,1), (2,{3}),(2,{1,3}),(3,1), (3,{3}),(3,{1,3}),(4,1), (4,{3}),(4,{1,3})}

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A large pool of adults earning their first driver’s license includes 50% low-risk drivers, 30% moderate-risk drivers, and 20% hi
Mamont248 [21]

Answer:

The probability that these four will contain at least two more high-risk drivers than low-risk drivers is 0.0488.

Step-by-step explanation:

Denote the different kinds of drivers as follows:

L = low-risk drivers

M = moderate-risk drivers

H = high-risk drivers

The information provided is:

P (L) = 0.50

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Now, it given that the insurance company writes four new policies for adults earning their first driver’s license.

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S = {HHHH, HHHL, HHHM, HHMM}

Compute the probability of the combination {HHHH} as follows:

P (HHHH) = [P (H)]⁴

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                = 0.0016

Compute the probability of the combination {HHHL} as follows:

P (HHHL) = {4\choose 1} × [P (H)]³ × P (L)

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Compute the probability of the combination {HHHM} as follows:

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                                                            + P (HHMM)

                                                  = 0.0016 + 0.016 + 0.0096 + 0.0216

                                                  = 0.0488

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Answer:

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k=\dfrac{m}5{}

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