The volume is 12 mL (0.012 L)
Before the aluminum was added, the water reached 132mL. After it was added, it reached 144. That means the Aluminum takes up (144-132)= 12mL of space.
The density = mass/volume. If the aluminum bar has a mass of 78g and volume of 0.012L, 78/0.012=6,500 g/L
S orbit can hold 2 electrons
Answer:
1.40 atm is the pressure for the gas
Explanation:
An easy problem to solve with the Ideal Gases Law:
P . V = n . R .T
T° = 370K
V = 17.3L
n = 0.8 mol
Let's replace data → P . 17.3L = 0.8mol . 0.082L.atm/mol.K . 370K
P = (0.8mol . 0.082L.atm/mol.K . 370K) / 17.3L = 1.40 atm
Aluminum has an atomic number of 13
with a mass number of 27
number of protons = mass number - atomic number = 27-13 = 14
