The volume of 0.125 mole of the gas at the same temperature and pressure 0.30 L
<h3>Data obtained from the question </h3>
- Initial mole (n₁) = 0.82 mole
- Initial volume (V₁) = 2 L
- New mole (n₂) = 0.125 mole
- Pressure = Constant
- Temperature = Constant
- New Volume (V₂) =?
<h3>How to determine the new volume</h3>
The new volume can be obtained as illustrated below
PV = nRT
Divide both side by P
V = nRT / P
Divide both side by n
V / n = RT / P = Constant
Thus,
V₁ / n₁ = V₂ / n₂
2 / 0.82 = V₂ / 0.125
Cross multiply
0.82 × V₂ = 2 × 0.125
Divide both side by 0.82
V₂ = (2 × 0.125) / 0.82
V₂ = 0.30 L
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Correct answer is
<span>D. One atom accepts electrons from another.</span>
This temperature in units of degree Celsius is..
-78° Celsius
