Answer:

this is the equation of the tangent at point (-1,1/e)
Step-by-step explanation:
to find the tangent line we need to find the derivative of the function g(x).

- we know that



this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'
to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1

using the equation of line:

we'll find the equation of the tangent line.
here (x1,y1) =(-1,1/e), and m = 3/e


this is the equation of the tangent at point (-1,1/e)
From the identity,
sin^2(x)+cos^2(x)=1
then
cos(x)=sqrt(1-sin^2(x))
where sin(x) is given as 0.42.
Note that the above answer applies to 0<x<90 degrees
Answer:
B
Step-by-step explanation:
To be a function every input must have exactly one output. There are two input values with 2, therefore this makes it not a function.
Answer:
5 1/5
Step-by-step explanation:
2 3/5 * 2= 5 1/5
mark brainliest :)