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pshichka [43]
3 years ago
7

Of the following expressions, which is equal to 6(√10)?

Mathematics
1 answer:
Inessa [10]3 years ago
8 0

Answer:

sqrt(360)

Step-by-step explanation:

sqrt(360)=sqrt(36*10)=sqrt(36)*sqrt(10)=6*sqrt(10)

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Martina, Jim, and Scott served a total of 121 orders Monday at the school cafeteria. Martina served 6 more orders than Scott. Ji
iris [78.8K]

Answer:

Martina 29, Scott 23 and Jim 69.

Step-by-step explanation:

We are told that:

Martina served six more X orders than Scott (X+6).

So, Scott served X orders.

And Jim served 3 times X order as Scott.

We will have then:

X + (X+6) + 3X = 121

5X + 6 = 121

5X = 121 - 6

5X = 115

X = 115/5

X = 23

So, Scott served 23 orders, Martina 29 and Jim 69.

8 0
2 years ago
INT1 4.1.1 Line of Best Fit (classwork)
Lorico [155]

Answer:

a. 2401.06

b. 37.54%

c. 56.3%

Step-by-step explanation:

hopefully this is right

*note: I think you forgot to convert 4-2 back into yards.

a. Robbie's field of view to the North end includes parts not on the football field. so to find the area of the football field he can see, we need to find:

total area of what Robbie sees - area of non football field Robbie sees

what you shaded represents the total of what Robbie sees. it's a triangle. area of a triangle is 1/2(b)(h) where h is distance away and b is width of view.

total area = 1/2(170)(30.92) = 2628.56 yd

area of non football field (pipe to South end)

= 1/2(50)(9.1) = 227.5

so 2628.56 - 227.5 = 2401.06

b. area found in part a / total area of football field

2401.06 / (120*53.3) = .3754

.3754 * 100 = 37.54%

c. the chance of Robbie seeing the touchdown depends on how much of the (North) endzone he can see.

area of north endzone is

10 * 53.3 = 533.

area Robbie sees in endzone is

2628.56 - 2328.48 = 300.08

(found by total area Robbie sees - area of non endzone Robbie sees)

300.08 / 533 = 0.563

= 56.3%

7 0
3 years ago
What is the product of? (7x^2)(2x^3+5)(x^2-4x-9)
pav-90 [236]
(7x^{2})(2x^{3} +5)( x^{2} -4x-9)

(14 x^{5} +35 x^{2})( x^{2} -4x-9)
=14 x^{7} -56 x^{6}-126 x^{5}+35 x^{4}-140 x^{3}-315 x^{2}
6 0
3 years ago
Read 2 more answers
According to the picture association of America, 4% of all moves advertising is on the internet and 1 10s of all movie advertisi
Annette [7]
1 of 10 is equivalent to 10% because 1/10 is .10 and .10•100% is 10% so the newspapers advertising is higher
7 0
3 years ago
Suppose that an object moves along the y-axis so that its location is y=x2+3x at time x. (Here y is in meters and x is in second
vfiekz [6]

Answer:

a) 13 m/s

b) (15  + h) m/s

c) 15 m/s

Step-by-step explanation:

if the location is

y=x²+3*x

then the average velocity from 3 to 7 is

Δy/Δx=[y(7)-y(3)]/(7-3)=[7²+3*7- (3²+3*3)]/4= 13 m/s

then the average velocity from x=6 to to x=6+h

Δy/Δx=[y(6+h)-y(6)]/(6+h-6)=[(6+h)²+3*(6+h)- (6²+3*6)]/h= (2*6*h+3*h+h²)/h=2*6+3= (15 + h) m/s

the instantaneous velocity can be found taking the limit of Δy/Δx when h→0. Then

when h→0 , limit Δy/Δx= (15 + h) m/s = 15 m/s

then v= 15 m/s

also can be found taking the derivative of y in x=6

v=dy/dx=2*x+3

for x=6

v=dy/dx=2*6+3 = 12+3=15 m/s

7 0
2 years ago
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