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SVEN [57.7K]
3 years ago
15

What does a very small equilibrium constant (K≪ 1) tell you about the reaction? View Available Hint(s) What does a very small eq

uilibrium constant ( 1) tell you about the reaction? The reaction mixture contains only reactants. The reaction mixture contains large amounts of products (relative to the amount of reactants) at equilibrium. The reaction mixture contains similar amounts of reactants and products at equilibrium. The reaction mixture contains large a
Chemistry
1 answer:
Effectus [21]3 years ago
5 0

Answer: The reaction mixture contains large amounts of reactants

Explanation:

The equilibrium constant (K) tells the degree to which a chemical reaction will progress.

So, a very small equilibrium constant (K≪ 1) tells of a reaction that has the concentration of the products as small, while the concentration of the reactants is large.

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How many particles of CuCr2O7 are present in a 64.5 gram sample?
kow [346]
<h3>Answer:</h3>

1.39 × 10²³ particles CuCr₂O₇

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 64.5 g CuCr₂O₇

[Solve] particles CuCr₂O₇

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of Cu - 63.55 g/mol

[PT] Molar Mass of Cr - 52.00 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of CuCr₂O₇ - 63.55 + 2(52.00) + 7(16.00) = 279.55 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 64.5 \ g \ CuCr_2O_7(\frac{1 \ mol \ CuCr_2O_7}{279.55 \ g \ CuCr_2O_7})(\frac{6.022 \cdot 10^{23} \ particles \ CuCr_2O_7}{1 \ mol \ CuCr_2O_7})
  2. [DA] Divide/Multiply [Cancel out units]:                                                         \displaystyle 1.38944 \cdot 10^{23} \ particles \ CuCr_2O_7

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.38944 × 10²³ particles CuCr₂O₇ ≈ 1.39 × 10²³ particles CuCr₂O₇

8 0
3 years ago
Oxygen is a non-mental?<br><br>True<br><br>False
valentinak56 [21]
True, they are non-metal

And it's metal, not mental XD
8 0
3 years ago
Read 2 more answers
Help please Thank You so much!
Irina18 [472]
If you count the number of electrons (small dots), you have the atomic number. In this case you have 11 so this atom is a sodium atom. Sodium has 1 valence electron (electron on the outer shell) and chlorine has 7. This means that if sodium gave one electron away and chlorine would obtain one electron, they would both have the (ideal) noble gas conformation (full outer shell).
4 0
4 years ago
If 12 gallons of gasoline cost $34.68, what is the unit price per gallon?
chubhunter [2.5K]
The answer is $2.89.

Since it’s asking for the unit price of one gallon and you have the total ($34.68 and 12 gallons), you would divide $34.68 from 12, which gives you $2.89.

34.68/12 = 2.89
5 0
2 years ago
Cow’s milk is 4.5% by mass of lactose. Calculate the mass of lactose present in 175 g of<br> milk
Reptile [31]

Answer:

7.875 grams

Explanation:

You multiply 175 g by .045

This gives you 7.875 grams of lactose

6 0
3 years ago
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