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Arte-miy333 [17]
3 years ago
10

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Chemistry
1 answer:
Diano4ka-milaya [45]3 years ago
5 0

Answer:

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It takes 486.0 kJ/mol to convert sodium atoms to Na+ ions. Sodium atoms absorb and emit light of wavelengths 589.6 and 590.0 nm.
solmaris [256]
We first calculate the energy contained in one photon of this light using Planck's equation:

E = hc/λ

E = 6.63 x 10⁻³⁴ x 3 x 10⁸ / 590 x 10⁻⁹
E = 3.37 x 10⁻²² kJ/photon

Now, one mole of atoms will excite one mole of photons. This means that 6.02 x 10²³ photons will be excited

(3.37 x 10⁻²² kJ/photon) x (6.02 x 10²³ photons / mol)

The energy released will be 202.87 kJ/mol
8 0
3 years ago
7. Assume that you have collected 867 L of nitrogen gas at STP. What is the mass of the nitrogen gas?
jekas [21]

Answer:

1083.6 g

Explanation:

At STP, 1 mol of any given mass will occupy 22.4 L.

With the information above in mind we can<u> calculate how many moles of nitrogen gas (N₂) are there in 867 L</u>:

  • 867 L ÷ 22.4 L/mol = 38.7 mol

Finally we convert 38.7 moles of N₂ into grams, using its molar mass:

  • 38.7 mol * 28 g/mol = 1083.6 g
6 0
3 years ago
Pls help, How is stoichiometry used to calculate amounts of substances in a chemical reaction?
Elden [556K]

Answer:

Thus, to calculate the stoichiometry by mass, the number of molecules required for each reactant is expressed in moles and multiplied by the molar mass of each to give the mass of each reactant per mole of reaction. The mass ratios can be calculated by dividing each by the total in the whole reaction.

Explanation: Stoichiometry is the field of chemistry that is concerned with the relative quantities of reactants and products in chemical reactions. For any balanced chemical reaction, whole numbers (coefficients) are used to show the quantities (generally in moles ) of both the reactants and products.

7 0
3 years ago
I need help with three questions plz help me out. If i don't past i won't progress onto the next grade.
8_murik_8 [283]
I can help I need the Qs
3 0
3 years ago
PLEASE HELP!! WILL MARK BRAINLIEST
Andrew [12]

Answer:

The answer to your question is below

Explanation:

                                         Trial 1                   Trial 2

mass of Mg                      0.255 g                0.353 g

mass of MgO                   0.418 g                 0.576 g

Chemical reaction

                                2Mg(s)    +  O₂(g)     ⇒   2MgO(s)

Question 1.

Atomic mass of Mg = 24.31 x 2 = 48.62 g

Molecular mass of MgO = 2(24.31 + 16) = 80.62 g

Trial 1

                          48.62 g of Mg ----------------- 80.62 g of MgO

                          0.255 g            ----------------   x

                          x = (0.255 x 80.62)/48.62

                          x = 0.422 g of MgO

Trial 2                48.62 g of Mg ----------------- 80.62 g of MgO

                          0.353 g            ----------------   x

                          x = (0.353 x 80.62)/48.62

                          x = 0.585 g of MgO

Question 2

Trial 1          

Percent yield = 0.418/0.422 x 100 = 99%

Trial 2

Percent yield = 0.576/0.585 x 100 = 98.5%

Question 3

Average = (99 + 98.5)/2

              = 98.75%

3 0
3 years ago
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