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MissTica
2 years ago
13

Which statement best describes the effect of low ionization energies and low electronegativities on metallic bonding?

Chemistry
2 answers:
kramer2 years ago
6 0
The statement that best describes the effect of low ionization energies and low electronegativities on metallic bonding is the first one - the valence electrons are easily delocalized. 
Due to these low energies and negativities, valence electrons can be moved around quite easily and their positions may be altered quite drastically. 
Rudik [331]2 years ago
3 0

Answer:

the valence electrons are easily delocalized.

Explanation:

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2 years ago
Use Lewis theory to determine the chemical formula for the compound formed between Mg and Br. Group of answer choices Mg3Br2 Mg2
IceJOKER [234]

Answer:

MgBr2

Explanation:

(Mg^2+) + (Br^1-)

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5 0
2 years ago
KHP is a monoprotic acid which provides one H+ ion. How would your results be affected if a diprotic acid (such as sulfuric acid
kari74 [83]

Explanation:

A.

In a diprotic acid, 2 moles of H+ ions is released. Therefore, number of moles of H+ in a diprotic acid = 2 × number of moles of H+ of monoprotic acid.

B.

Equation of the reaction

2NaOH + H2SO4 --> Na2SO4 + 2H2O

Number of moles of H2SO4 = molar concentration × volume

= 0.75 × 0.0105

= 0.007875 moles.

By stoichiometry, since 1 mole of H2SO4 reacts with 2 moles of NaOH. Therefore, number of moles of NaOH = 2 × 0.007875

= 0.01575 moles.

Molar concentration of NaOH = number of moles ÷ volume

= 0.01575 ÷ 0.0175

= 0.9 M of NaOH.

7 0
2 years ago
PLEASE HELP ASAP!
egoroff_w [7]

Answer:

Lithium fluoride i think but I am not really sure

But it should be Lithium fluoride

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3 0
2 years ago
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