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babunello [35]
3 years ago
14

Please match the orbital type with the correct number of orbitals

Chemistry
1 answer:
saul85 [17]3 years ago
7 0
Hi there!

p = e-3
s = f-1
f = i-7
d = g-5

Hope that helps!
Brady
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Please help me thanks:)
lianna [129]

Answer:

where it goes

Explanation:

3 0
2 years ago
Read 2 more answers
I don't know how to do this, pls help!
Aliun [14]
Cations from smallest to largest
Li⁺ ,Na⁺, K⁺ (from Periodic Table, the bigger number of period, the bigger size, of atom, so the bigger size of cation)

1) LiF smaller  cation then KF
1,036                                 <span>853
</span><span>The lattice energy increases as cations get smaller, as shown by LiF and KF.
</span><span>I think this one should be correct answer, because the compared substances have also the same anion, and we can compare cations in them.

2) The same cation Li , so wrong statement.

3)</span>The same cation Na , so wrong statement.

4) NaCl smaller cation then KF
  786                                   853
7 0
3 years ago
Read 2 more answers
you are given an unknown gaseous binary compound. when 10.0g of the compound isburned in excess oxygen, 16.3g of water is produc
Flauer [41]
Since the compound has 1.38 time that of oxygen gas at the same conditions of temperature and pressure, we have the relationship:
MW/MWoxygen = 1.38
MW = 44.16

Since there is water formed during the reaction, the formula of the compound must be:
XaHb
where a and b are the coefficients of each element.

If the compound reactions with oxygen forming water and an oxide of the element X, the combustion reaction must be:
XaHb + ((2a + (b/2))/2) O2 = a (XO2) + (b/2)(H2O)
Using dimensional analysis:
10 (1/44.16) (b/2 / 1) (18) = 16.3
Solving for b:
b = 8

The compound now is XaH8. Most probably, the compound is C3H8 since it has a molecular formula of 44 and it reacts with O2 to form water and CO2.
5 0
3 years ago
What would most accurately measure the volume of water or other liquid?
Afina-wow [57]

Answer:

D. Graduated Cylinder

Explanation:

7 0
2 years ago
How many moles of propane gas would be present in 11 grams<br> of the gas at standard conditions?
Akimi4 [234]
The molar mass is usually referred to with
M
, while the mass is referred to as
m
. The amount of substance is
n
. This gives you the following relationship:
=
M
=
m
n

Since you have given (C3H8)=11 g
m
(
C
3
H
8
)
=
11

g
and you already looked up (C3H8)=44.1 gmol−1
M
(
C
3
H
8
)
=
44.1

g
m
o
l
−
1
, you can use this formula to determine (C3H8)
n
(
C
3
H
8
)
.

In this question it is quite hard to explain the use of significant figures. Those are used to imply a certain inaccuracy. Not enough information is given by the question, as of how accurate the measurement is. It is a mere exercise of converting one property into another. Here you should not worry about it.
5 0
3 years ago
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