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LenaWriter [7]
3 years ago
10

A crowbar makes our work easier by multiplying effort true or false​

Physics
1 answer:
OLEGan [10]3 years ago
6 0

Answer:

True

Explanation:

A crowbar makes our work easier by multiply effort because it belongs to first class lever.

And first class lever makes work easier by multiplying the effort

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a certain projetor uses a concave mirror for projecting an object's image on a screen .it produces on image that is 4 times bigg
IrinaK [193]

Answer:

f = 1 m

Explanation:

The magnification of the lens is given by the formula:

M = \frac{q}{p}

where,

M = Magnification = 4

q = image distance = 5 m

p = object distance = ?

Therefore,

4 = \frac{5\ m}{p}\\\\p = \frac{5\ m}{4}\\\\p = 1.25\ m

Now using thin lens formula:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}\\\\\frac{1}{f} = \frac{1}{1.25\ m}+\frac{1}{5\ m}\\\\\frac{1}{f} = 1\ m^{-1}\\\\

<u>f = 1 m</u>

6 0
2 years ago
What is one result of meiosis?
Nonamiya [84]
Hello,

It's D! hope I helped.
8 0
3 years ago
Honeybees acquire a charge while flying due to friction with the air. A 100 mg bee with a charge of +23 pC experiences an electr
Sedbober [7]

Answer:

(A) ratio of electric force to weight will be  23.469\times 10^{-10}

(b) Electric field will be E=4.26\times 10^{10}N/C

Explanation:

We have given mass of bee = 100 mg  = m=100\times 10^{-3}=0.1kg

Charge on bee q=23pC=23\times 10^{-12}C

Electric field E = 100 N/C

Weight of the bee W=mg=0.1\times 9.8=0.98N

Electric force on the bee F=qE=23\times 10^{-12}\times 100=23\times 10^{-10}N

So the ratio of electric force on the bee and weight is =\frac{F}{W}=\frac{23\times 10^{-10}}{0.98}=23.469\times 10^{-10}

(B) To hold the bee in air electric force must be equal to weight of bee

So mg=qE

0.1\times 9.8=23\times 10^{-12}E

E=4.26\times 10^{10}N/C

4 0
3 years ago
A typical helicopter has four blades that rotate at 334 rpm and have a total kinetic energy of 4.55 105 J. What is the magnitude
djyliett [7]

Answer:

the magnitude of the total angular momentum of the blades is <em>743.71 kg·m²</em>

Explanation:

Converting the angular speed into radians per second:

ω = 334 rpm · (2π rad / 1 rev) · (1 min / 60 s)

ω = 34.98 rad/s

The rotational kinetic energy of the blades is given by:

EK = 1/2 I ω²

where

  • I is the moment of inertia
  • ω is the angular speed

Therefore, rearranging the above equation, we get:

1/2 I ω² = EK

I ω² = 2 EK

I = 2(EK) / ω²

I = 2(4.55 × 10⁵ J) / (34.98 rad/s)²

<em>I = 743.71 kg·m²</em>

<em></em>

Therefore, the magnitude of the total angular momentum of the blades is <em>743.71 kg·m²</em>.

5 0
3 years ago
The equation of the line perpendicular to the y-axis that passes through the point (–5, 1) is y = 1. True or false.
lara31 [8.8K]

That's true. 

If the line is perpendicular to the y-axis, then it's horizontal,
and parallel to the x-axis. 

Every point on the line has the same y-coordinate.  If the point  (-5, 1) 
is on the line, then all the points  (any number, 1) are also on it. 
The equation of the line is 
                                               [ y = 1 ] .

8 0
2 years ago
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