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solmaris [256]
3 years ago
5

How does a mathematical model help you understand the science concepts? Give an example.

Physics
1 answer:
sveta [45]3 years ago
4 0
Usually describes a system by a set of variables in a set of equations established relationships between the variables and variables maybe of many types real or integer numbers Boolean values of strings for example
You might be interested in
Newton's Law of Gravitation says that the magnitude F of the force exerted by a body of mass m on a body of mass M is F = GmM r2
Nookie1986 [14]
<h2>Answers:</h2>

<h2>(a) </h2>

According to Newton's Law of Gravitation, the Gravity Force is:

F=\frac{GMm}{{r}^{2}}     (1)

This expression can also be written as:

F=GMm{r}^{-2}    (2)

If we derive this force F respect to the distance r between the two masses:

\frac{dF}{dr}dFdr=\frac{d}{dr}(GMm{r}^{-2})dr     (3)

Taking into account GMm are constants:

\frac{dF}{dr}dFdr=-2GMm{r}^{-3}     (4)

Or

\frac{dF}{dr}dFdr=-2\frac{GMm}{{r}^{3}}     (5)

<h2> (b) dF/dr represents the rate of change of the force with respect to the distance between the bodies.  </h2><h2 />

In other words, this means how much does the Gravity Force changes with the distance between the two bodies.

More precisely this change is inversely proportional to the distance elevated to the cubic exponent.

As the distance increases, the Force decreases.

<h2>(c) The minus sign indicates that the bodies are being forced in the negative direction.  </h2>

This is because Gravity is an attractive force, as well as, a central conservative force.

This means it does not depend on time, and both bodies are mutually attracted to each other.

<h2>(d) </h2>

In the first answer we already found the decrease rate of the Gravity force respect to the distance, being its unit N/km:

\frac{dF}{dr}dFdr=-2\frac{GMm}{{r}^{3}}     (5)

We have a force that decreases with a rate 1 \frac{dF_{1}}{dr}dFdr=4N/km when r=20000km:

4N/km=-2\frac{GMm}{{(20000km)}^{3}}     (6)

Isolating -2GMm:

-2GMm=(4N/km)({(20000km)}^{3})     (7)

In addition, we have another force that decreases with a rate 2 \frac{dF_{2}}{dr}dFdr=X when r=10000km:

XN/km=-2\frac{GMm}{{(10000km)}^{3}}     (8)

Isolating -2GMm:

-2GMm=X({(10000km)}^{3})     (9)

Making (7)=(9):

(4N/km)({(20000km)}^{3})=X({(10000km)}^{3}       (10)

Then isolating X:

X=\frac{4N/km)({(20000km)}^{3}}{{(10000km)}^{3}}  

Solving and taking into account the units, we finally have:

X=-32N/km>>>>This is how fast this force changes when r=10000 km

7 0
4 years ago
Read 2 more answers
*Look at attachment for photo of object**
prohojiy [21]

A. The magnitude of the spring force (in N) acting upon the object is 15.9 N

B. The magnitude of the object's acceleration (in m/s²) is 30.58 m/s²

C. The direction of the acceleration vector points toward the equilibrium position (i.e., to the left in the figure).

<h3>A. How to determine the force </h3>
  • Extension (e) = 0.150 m
  • Spring constant (K) = 106 N/m
  • Force (F) = ?

F = Ke

F = 106 × 0.15

F = 15.9 N

<h3>B. How to determine the acceleration</h3>
  • Mass (m) = 0.52 Kg
  • Force (F) = 15. 9 N
  • Acceleration (a) =?

F = ma

Divide both sides by m

a = F / m

a = 15.9 / 0.52

a = 30.58 m/s²

<h3>C. How to determine the direction of the acceleration vector</h3>

Considering the diagram, we can see that the spring was pulled away from the equilibrium point.

Thus, when the spring is released, it will move toward the equilibrium point. This is also true about the acceleration.

Therefore, we can conclude that the direction of the acceleration vector is towards the equilibrium point.

Learn more about spring constant:

brainly.com/question/9199238

#SPJ1

3 0
2 years ago
molecules on an acid base indicator react chemically with ions in a solution causing the indicator to change color. which ions i
Maksim231197 [3]
The appropriate response is hydrogen ions. It entirely, the core of a hydrogen particle isolated from its going with an electron. The hydrogen core is comprised of a molecule conveying a unit positive electric charge, called a proton.


I hope the answer will help you. 
5 0
3 years ago
Read 2 more answers
If energy decreases in one part of a system, what will happen?
Flauer [41]
C. because energy can not be created or destroyed, but transformed/transferred to maintain equilibrium.
6 0
4 years ago
Suppose the acceleration of an elevator is 1/2 g upward, then what is the reading on the scale in the elevator.
Irina-Kira [14]

Answer:

c. 3/2 mg

Explanation:

Given that the acceleration of an elevator is 1/2 g upward.

The reading on the scale of the elevator is the net external force acting on the elevator.

Let the force F acting on the elevator as shown,

By using Newton's 2nd law, F_{net}=ma

where, F_{net} is the net force acting on the elevator.

m is the mass of the elevator,

a is the acceleration of the elevator, as given a=1/2 g upward.

So, F_{net}=m\times \frac 1 2 g

F-mg=m\times \frac 1 2 g \\\\F=mg+ \frac 1 2 mg \\\\F= \frac 3 2 mg.

So, the reading on the scale in the elevator is \frac 3 2 mg.

Hence, option (c) is correct.

4 0
3 years ago
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