A compression is where the particles in the air are closer together, so where those black lines are closer together.
A rarefaction is the opposite, where they're spread out.
The wavelength is the distance between two compressions or rarefactions (i.e. two peaks or troughs on a graph), therefore thats the horizontal arrows.
The amplitude is the distance from the centre of the wave to the peak or trough, so that is the vertical distance on the diagram.
Answer:
The coefficient of rolling friction for the tire under low pressure is 0.0342.
Explanation:
Two bicycle tires are set rolling with the same initial speed of 4.00 m/s
Final speed of both the bicycle, speed is reduced by half is measured, v = 2 m/s.
Here,

Using third equation of motion as :

So, the coefficient of rolling friction for the tire under low pressure is 0.0342.
Use Fnet=ma. Apply it to the vertical components of all the forces acting on the ball and since tension is the same on both wires you should be able to factor it out and solve for it. Picture below
Answer:
The object will sink in the liquid in beaker 1.
The object will float in the liquid in beaker 2
Explanation:
The density of an object relative to the density of a fluid determines if the object floats or sink in a fluid. The density of a material is the measure of the amount of mass of that material packed into a unit volume of that material.
For the beaker 1, the liquid in this beaker has a density of 0.5 g/cc, which is lesser than the density of the object (0.85 g/cc). This means that the object will add more mass than there should be to the volume of the space it displaces within the field. This results in the object sinking in the fluid.
For beaker 2, the liquid in this beaker has a density of 1 g/cc, which is more than the density of the object (0.85 g/cc). This means that the object will add less mass than there should be to the volume of the space it displaces within the field. This results in the object floating in the fluid.
Answer:
n = 1.56
Explanation:
The total reflection attempts occurs when a light beam passes from a medium with a higher index to a medium with a lower nest, at an angle where it occurs we can find them by the refractive relationship
n₁ sin θ₁ = n₂ sin θ₂
n1 = n2 / sin θ₁
For this relationship to be fulfilled, the liquid index must be greater than the air index divided by the sine of the critical angle
Let's use trigonometry to find angle
tan θ = y / x
θ = tan⁻¹ 7.2 / 8.6
θ = 39.94º
n₁ = 1 / sin 39.94
n = 1.56
This is the refractive index of the liquid