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Westkost [7]
3 years ago
13

Suppose x + y = 13 and the value of x increases by 4. If their sim remain the same, what must happen to the value of y?

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
6 0
The value of y would decrease if x increases and the sum stays the same.
Ivahew [28]3 years ago
4 0
If the value of x increases by 4 and the sum is constant or the same, the value of y will decrease. Ex: if x=1 increase by 4 so, 5+y=13 then y=8,if x increase by 4, 9+y=13, then y=4.
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I need help on this question
Troyanec [42]

Hello!

In a taxi cab, the longer you ride, the more it costs. This would make a scatter plot go through Quadrant 1.

Therefore, it would have a positive relationship

I hope this helps!

5 0
3 years ago
The point slope of a line that has a slope of -2 and passes through point (5,-2) is shown below. Which equation is in slope inte
kramer
Y + 2 = -2(x - 5)

Simplify.

y + 2 = -2x + 10

Subtract 2 from both sides.

y = -2x + 10 - 2

Simplify.

y = -2x + 8 → Slope-intercept form

Our answer is the second option : y=-2x+8

~Hope I helped!~
 

7 0
3 years ago
Read 2 more answers
True or False, In Euclidean geometry, there is only one equilateral triangle
docker41 [41]

True, In Euclidean geometry an equilateral triangle must be a 60-60-60 triangle.

Hope This Helps!!!

5 0
3 years ago
This is a pre calculus question that I need help with, serious answer PLEASE and thank you! Will give brainliest.
IRISSAK [1]

The wording of this question is a bit confusing... You can't write a sequence in sigma notation, but rather a series or sum. I think the question is asking you to write the sum of the sequence,

\dfrac12,\dfrac14,\dfrac18,\ldots,\dfrac1{64}

which would be

\dfrac12+\dfrac14+\dfrac18+\cdots+\dfrac1{64}

in sigma notation.

To do this, notice that the denominator in each term is a power of 2, starting with 2^1=2 and ending with 2^6=64. So in sigma notation, this series is

\displaystyle\sum_{n=1}^6\frac1{2^n}

4 0
3 years ago
Write an equation of the line that passes through (2 -5) and is parallel to the line 2y=3x+10
andrey2020 [161]

Step-by-step explanation:

Given equation is

2y = 3x + 10

3x - 2y + 10 = 0 .....i)

Any line parallel to line I) is

3x - 2y + k = 0 ......ii)

As the line two passes through the point ( 2 , - 5 ) Now substituting the values

3 * 2 - 2 * ( - 5) + k = 0

6 + 10 + k = 0

16 + k = 0

k = - 16

Now putting the value of k in equation two

3x - 2y + 16 = 0 is the required equation.

Hope it will help :)❤

8 0
3 years ago
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