Answer:
O C. Deposition
D. Freezing
Explanation:
I hope it helps <3
I got it correct in Ape x
<span>52.7 ml
First, determine how many moles of NaCl you have
Atomic weight sodium = 22.989769
Atomic weight chlorine = 35.453
Molar mass NaCl = 22.989769 + 35.453 = 58.442769 g/mol
Moles NaCl = 15.4 g / 58.442769 g/mol = 0.263505653 mol
Now molarity is defined as moles/liter, so let's set up an equation for the number of liters we can make.
molarity = moles/liter
Substitute the known values
5.00 = 0.263505653/liter
And solve for liters
5.00 = 0.263505653/liter
5.00* liter = 0.263505653
liter = 0.263505653/5.00
liter = 0.052701131
So you can make 0.0527 liters of the solution. Or 52.7 ml</span>
Answer:
3,3-Dimethyloct-4-yne · Contents · 1Structures · 2Names and Identifiers · 3Chemical and Physical Properties · 4Related Records · 5 Patents · 6 ..
Answer:
The maximum amount of work that can be done by this system is -2.71 kJ/mol
Explanation:
Maximum amount of work denoted change in gibbs free energy 
during the reaction.
Equilibrium concentration of B = 0.357 M
So equilibrium concentration of A = (1-0.357) M = 0.643 M
So equilibrium constant at 253 K, ![K_{eq}= \frac{[B]}{[A]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%20%5Cfrac%7B%5BB%5D%7D%7B%5BA%5D%7D)
[A] and [B] represent equilibrium concentrations
When concentration of A = 0.867 M then B = (1-0.867) M = 0.133 M
So reaction quotient at this situation, 
We know, 
where R is gas constant and T is temperature in kelvin
Here R is 8.314 J/(mol.K), T is 253 K, Q is 0.153 and 
is 0.555
So, 
= -2710 J/mol
= -2.71 kJ/mol
Answer:
speed and how slidey things are
Explanation:
