When OH- and H+ ions are brought together, they quickly
combine to form water molecules.
a. True
b. False
The statement “When OH- and H+ ions are brought together,
they quickly combine to form water molecules” is true. The answer is letter A.
Explanation:
a. Vanillin(4-hydroxy-3-methoxybenzaldehyde):
In its structure hydroxl group will be present on para position of the benzaldehyde ring and methoxy group on meta position.
b. Thymol (2-isopropyl-5-methylphenol):
In its structure isopropyl group will be present on ortho position of the phenol ring and methyl group on meta position.
c. Carvacrol (5-isopropyl-2-methylphenol):
In its structure isopropyl group will be present opposite to methyl group which is present ortho position in a phenol ring.
d. Eugenol (4-allyl-2-methoxyphenol):.
In its structure allyl group will be present on para position of the phenol ring and methoxy group on ortho position.
e. Gallic acid (3,4,5-trihydroxybenzoic acid):
In its structure hydroxyl group will be present on both meta positions and on para position of the benzoic acid ring.
f. Salicyl alcohol (o-hydroxybenzyl alcohol):
In its structure, 
group is linkedto benzene ring and in respect to that hydroxyl group is present at ortho position of the ring.
Answer: 5.18
Explanation:
Mathematically, pOH is expressed as
pH = -log(OH-)
where OH-is the concentration of hydroxide ion
So, pOH calculations are as follows
pOH = -log(1.50x10-9 M)
pOH = -(-8.82)
pOH = 8.82 [the two minus signs cancelled out]
Since pOH = 8.82; apply the formula
pH + pOH = 14 to get pH of the solution
Hence, pH + pOH = 14
pH + 8.82 = 14
pH = 14 - 8.82
pH = 5.18
Thus, the pH of a solution with a 1.50x10-9 M hydroxide ion concentration is 5.18 (slightly acidic)
A very electronegative atoms has a strong ability of attracting electrons towards itself. As a result, it would gain electrons more than it usually has. Therefore, it would form an anion, or a negatively charge ion. These ions readily accepts electrons from the valence of other elements.
