B
1 mile=4 poles
if 5 poles pass by than she´s going around 1.25 miles per min
rounded up = 1.3 mil/min
Answer:
D. length × width
Explanation:
eg. 30 cm(length) × 20cm(width) = 600cm²
Answer:
MgCl2 > C4H9OH > CH4 > C3H8.
Explanation:
Alkanes do not form hydrogen bonds and are insoluble in polar solvents e.g water. The hydrogen bonds between water molecules are move away from an alkane molecule and this worsens as their Carbon chain / molecular weight increases.
MgCl2 is soluble in water. Water essentially breaks down the ionic crystal lattice and the resulting solution is slightly basic.
Alcohols are generally soluble in water and this is because of the -OH group and its ability to form hydrogen bonds with water molecules. As applied to alkanes, as the carbon chain in the alkyl group increases, the solubility decreases.
From the most soluble to the least soluble,
MgCl2 > C4H9OH > CH4 > C3H8.
Answer:
no equivalent peak, upfield between 0 and 3 ppm
Explanation:
NMR stands for nuclear magnetic resonance. It is a spectroscopic technique that is used for observing the local magnetic fields around an atomic nuclei. It is used to study the chemical, physical and biological properties of the matter.
In the context, the structures of the benzaldehyde and the benzyl alcohol are distinguished by the proton NMR. The hydrogen atom of aldehyde appears downfield between 9 and 11 ppm and also there is no equivalent peak for the alcohol.
The methylene hydrogens will only be significant upfield between the 0 and 3 ppm peak between the given structures.
Answer:
235 g
Explanation:
From the question;
- Volume is 400.0 mL
- Molarity of a solution is 4.25 M
We need to determine the mass of the solute K₂CO₃,
we know that;
Molarity = Number of moles ÷ Volume
Therefore;
First we determine the number of moles of the solute;
Moles = Molarity × volume
Moles of K₂CO₃ = 4.25 M × 0.4 L
= 1.7 moles
Secondly, we determine the mass of K₂CO₃,
We know that;
Mass = Moles × Molar mass
Molar mass of K₂CO₃, is 138.205 g/mol
Therefore;
Mass = 1.7 moles × 138.205 g/mol
= 234.9485 g
= 235 g
Thus, the mass of K₂CO₃ needed is 235 g
