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3 years ago

I have forgotten how to math? help? brainlest to first correct answer.

Mathematics

1 answer:

Ann [662]3 years ago

6 0

Answer:

90 meters squared

Step-by-step explanation:

First you multiply 10*4.5=45

Then you multiply 45 and 2 because 1cm=2m

45*2=90

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Please help!!! 98 Brainliest Points to anyone who can help with these!!

Talja [164]

The distance between them is 4.0
The equation would be 1.5-(-2.5)=d

Hope that helps?

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3 years ago

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

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3 years ago

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Yuliya22 [10]

Answer:

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3 years ago

If two lines are perpendicular, which statement must be true? A.The slopes of the two lines are equal. B.The slopes of the two l

dangina [55]

Answer:

Option D is correct that is The Slopes of two lines are negative reciprocals.

Step-by-step explanation:

Perpendicular lines are the lines which intersect each other at right angle or make 90° angle with each other.

we that the Slope of perpendicular lines are equal to -1

Therefore, Option D is correct that is The Slopes of two lines are negative reciprocals.

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OverLord2011 [107]

Answer:

Step-by-step explanation:

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