Answer:
6
/19
≅ 0.3157895
Step-by-step explanation:
Answer:
x = -3
Step-by-step explanation:
15 - 2x = -7x
add 2x
15 = -5x
divide by -5
-3 = x
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identities
secx = 
, cosecx = 
cotx = 
, tanx = 
Consider the left side
secA cosecA - cotA
= 
× 
- 
= 
-
= 
= 
( cancel sinA on numerator/ denominator )
= 
= tanA = right side ⇒ proven
Answer:
Liquid R has a mass of of 1 kg at a temperature of 30°c kept in a refrigerator to freeze . Given the specific heat capacity is 300 J kg-¹ °c-1 and the freezing point is 4°c . Calculate the heat release by liquid R.
Step-by-step explanation:
Liquid R has a mass of of 1 kg at a temperature of 30°c kept in a refrigerator to freeze . Given the specific heat capacity is 300 J kg-¹ °c-1 and the freezing point is 4°c . Calculate the heat release by liquid R.
