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Soloha48 [4]
3 years ago
10

The pressure in a water line is 1500 kPa. What is the line pressure in (a) lb/ft2units and (b) lbf/in2(psi) units?

Engineering
1 answer:
n200080 [17]3 years ago
3 0

Answer:

Part A:

1500\ KPa= 31328.145 \frac{lb}{ft^2}

Part B:

1500 KPa=217.55656 \frac{lb}{in^2}(Psi)

Explanation:

Part A:

Line Pressure is 1500 KPa

We need a conversion factor which converts KPa to lb/ft^2.

20.88543 \frac{lb}{ft^2}= 1\ KPa

In order to convert 1500 KPa to lb/ft^2, we proceed as:

1\ KPa=20.88543 \frac{lb}{ft^2} \\1500\ KPa= 1500 KPa*20.88543 \frac{lb}{ft^2.KPa}\\1500\ KPa= 31328.145 \frac{lb}{ft^2}

1500 KPa is 31328.145 lb/ft^2

Part B:

We will use the same procedure we did in Part A:

1 ft= 12 in

(1\ ft)^2=(12\ in)^2\\1 ft^2=144 in^2

Converting 1500 KPa\  into\  \frac{lb}{in^2}

1500\ KPa= 1500 KPa*20.88543 \frac{lb}{ft^2.KPa} * \frac{ft^2}{144\ in^2}

1500 KPa=217.55656 \frac{lb}{in^2}(Psi)

1500 KPa is 217.55656 lb/in^2 (psi)

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Answer:

Zero 1 = -1

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Explanation:

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T.F = k [N(s)] ÷ [D(s)]

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k [N(s)] = 4s² + 16s + 12 = 4[s² + 4s + 3]

it is evident that

Gain = k = 4

N(s) = (s² + 4s + 3) = (s² + s + 3s + 3)

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The zeros are -1 and -3

D(s) = s⁴ + 12s³ + 44s² + 48s

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The roots are then, 0, -2, -4 and -6.

Hope this Helps!!!

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4 years ago
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Air, at a pressure of 700 kPa and a temperature of 80°C, flows through a convergent– divergent nozzle. The inlet area is 0.005 m
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Answer: The complete part of the question is to find the exit velocity

Explanation:

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4 years ago
The charpy test determines?
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Answer:

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Explanation:

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Answer:

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Explanation:

Hello,

In this case by combining the first and second law of thermodynamics for this ideal gas, we can obtain the following expression for the differential of the specific entropy <em>at constant pressure</em>:

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