The number of atoms that are in 0.32 g of copper are
3.01 x10^21 atoms
<u><em>calculation</em></u>
<u><em> </em></u>Step 1: find the number of moles of Copper
moles = mass/molar mass
= 0.32 g /63.5 g/mol=0.005 moles
Step 2: use the Avogadro's constant to determine the number of atom
in 0.005 moles of Cu
that is according to Avogadro's law 1 mole =6.02 x10^23 atoms
0.005 moles=? atoms
by cross multiplication
= (0.005 moles x 6.02 x10^23 atoms) / 1 mole= 3.01 x10 ^21 atoms
The reaction formula of this is N2 + 3H2 = 2NH3. So the ratio of mol number of N2 and NH3 is 1:2. The mol number of NH3 is 2.27*2=4.54 mol. So the mass is 4.54*17=77.18 g.
The statements in accordance with the law of conservation of charge are:
A. The total charge of the reactants and products must be equal
B. The net charge of an isolated system remains constant
Both of these statements follow the law of conservation of charge which states that charge may neither be created nor destroyed, due to which the total charge in an isolated system (one in which charge can not move in or out of) remains constant.
Answer:
3.4 × 10²³ molecules of CBr₄
Explanation:
Given data:
Mass of CBr₄ = 189 g
Number of molecules = ?
Solution:
First of all we will calculate the number of moles.
Number of moles = mass / molar mass
Number of moles = 189 g/ 331.63 g/mol
Number of moles = 0.6 mol
Now the given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
Foe 0.6 moles of CBr₄:
0.6 mol × 6.022 × 10²³ molecules of CBr₄ / 1 mol
3.4 × 10²³ molecules of CBr₄
Answer:
Magnetism, and electrical charge, and gravitation are examples of forces that act at a distance. There are other such forces at the atomic level.
