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Naily [24]
3 years ago
14

Which statement is true for photosynthesis

Chemistry
1 answer:
grigory [225]3 years ago
5 0

Answer: all  of them duuuuuuuuuuuuuuuuuuuuuuuuuuuuu

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A mineral consisted of 29.4% calcium, 23.5% sulfur and 47.1% oxygen. What is the empirical formula?
inessss [21]
Step  one  calculate  the  moles  of  each  element
that  is  moles= %  composition/molar  mass
molar  mass  of    Ca  =  40g/mol,     S=  32  g/mol ,   O=  16 g/mol

moles  of      Ca = 29.4 /40g/mol=0.735 moles,      S= 23.5/32  =0.734 moles,  O= 47.1/16= 2.94   moles

calculate  the mole  ratio  by  dividing   each  mole with  smallest  mole   that   is  0.734
Ca=  0.735/0.734= 1,      S=  0.734/0.734 =1,   O  = 2.94/  0.734= 4
therefore  the  emipical  formula  =  CaSO4
5 0
3 years ago
Chemists use activity series to determine whether which type of reaction will occur?
ruslelena [56]
Single replacement reactions.  For example copper is more reactive than silver.  So a copper wire in a silver solution will cause the silver to become a metal again.
5 0
3 years ago
Read 2 more answers
The number of grams per mole of something is known as?​
Whitepunk [10]

Answer:

Judging from the wording of he question, you mean units. If that is indeed the case, the answer is g/Mol (grams per mol)

Let me know if my interpretation is incorrect and please tell me what you are actually trying to find.

7 0
3 years ago
All of these could be considered disadvantages of nuclear power plants except
ki77a [65]

Answer:

B

Explanation:

Mark as brainliest ;)

8 0
3 years ago
How many grams are in 3.14 x 1015 molecules of CO?
Vesnalui [34]

Answer:

Explanation:

Not Many

1 mol of CO has a mass of

C = 12

O = 16

1 mol = 28 grams.

1 mol of molecules = 6.02 * 10^23

x mol of molecules = 3.14 * 10^15        Cross multiply

6.02*10^23 x = 1 * 3.14 * 10^15             Divide by 6.02*10^23

x = 3.14*10^15 / 6.02*10^23

x = 0.000000005 mols

x = 5*10^-9

1 mol of CO has a mass of 28

5*10^-9 mol of CO has a mass of x                        Cross Multiply

x = 5 * 10^-9 * 28

x = 1.46 * 10^-7 grams

Answer: there are 1.46 * 10-7 grams of CO if only 3.14 * 10^15 molecules are in the sample

5 0
3 years ago
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