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Yuri [45]
3 years ago
14

Calculate q (in units of joules) when 1.850 g of water is heated from 22 °C to 33 °C

Chemistry
1 answer:
lisov135 [29]3 years ago
5 0
The answer is 7345 g
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Can someone help me pls
juin [17]
I know that computer engineering has a shortage of workers still
5 0
3 years ago
If a gaseous mixture is made by combining 2.74 g Ar 2.74 g Ar and 4.90 g Kr 4.90 g Kr in an evacuated 2.50 L container at 25.0 ∘
krok68 [10]

Answer:

Hfhfj

Explanation:

7 0
3 years ago
An oxidation-reduction reaction that is also a synthesis reaction
Aleonysh [2.5K]

The example of a chemical combination that can also be said to be a synthesis reaction is; 2Mg(s) +O_{2} (g) -- > 2 MgO(s)

<h3>What is a synthesis reaction?</h3>

We know that the meaning of the synthesis reaction is quite central as we attempt to answer the question that is lying right before us here. If we are talking about the synthesis reaction then our mind must have to go to the kind of reaction in which there is the combination of two or more so as to produce a single compound.

As we are talking about the synthesis reaction, we would have to look at the reaction that would give rise to a single product as it has been written. Let us also recall that we have been told that the reaction is a  oxidation-reduction reaction thus there is a change in oxidation number in the process of the reaction as shown.

Learn more about synthesis reaction:brainly.com/question/16987748

#SPJ1

7 0
1 year ago
Question 2 (2 points)
inysia [295]

Answer:

v = 46.5 m/s

Explanation:

Given data:

Mass of car = 1210 kg

Momentum of car = 56250 kg m/s

Velocity of car = ?

Solution:

Formula:

p = mv

p = momentum

m = mass

v = velocity

Now we will put values in formula:

56250 kg m/s  = 1210 kg × v

v = 56250 kg m/s / 1210 kg

v = 46.5 m/s

So a car having mass of 1210 kg with momentum 56250 kg m/s having 46.5 m/s velocity.

5 0
3 years ago
8). How many moles of oxygen gas must be placed in a 35.0 L container in order
klemol [59]

Answer:

4.1 moles

Explanation:

Applying

PV = nRT................ equation 1

Where P = pressure, V = volume, n = number of moles, R = molar gas constant, T = Temperature.

make n the subject  of the equation

n = PV/RT.............. Equation 2

From the question,

Given: V = 35 L , P = 2.8 atm, T = 15 °C  = (15+273) = 288 K, R = 0.083 L.atm/K.mol

Substitute these values into equation 2

n = (35×2.8)/(0.083×288)

n = 4.1 moles

5 0
3 years ago
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