Ask question

Ask question

All categories

3 years ago

12

Two numbers are in ratio of 3 : 4.If their sum is 133 ,find the number. Help

2 answers:

sergiy2304 [10]3 years ago

6 0

<em>Let </em><em>the </em><em>two </em><em>numbers </em><em>be </em><em>3x </em><em>and </em><em>4x</em>

<em>sum </em><em>=</em><em>3x </em><em>+</em><em> </em><em>4x </em><em>=</em><em> </em><em>7x</em>

<em>7x </em><em>=</em><em> </em><em>133</em>

<em>x=</em><em> </em><em>19</em>

<em>the </em><em>numbers </em><em>are </em><em>:</em>

<em>3(</em><em>1</em><em>9</em><em>)</em><em> </em><em>=</em><em> </em><em>57</em>

<em>4(</em><em>1</em><em>9</em><em>)</em><em> </em><em>=</em><em> </em><em>76</em>

Alik [6]3 years ago

4 0

Answer:

57 and 76

Step-by-step explanation:

Given the ratios are 3 : 4 = 3x : 4x, then

3x + 4x = 133

7x = 133 ( divide both sides by 7 )

x = 19

The numbers are

3 × 19 = 57 and 4 × 19 = 76

You might be interested in

Molly has five cupcakes jack has teo rhey combinde rhat what do they get

inessss [21]

They have seven cup cakes!

5 0

3 years ago

Read 2 more answers

Work out the size of one of the exterior angles

hodyreva [135]

<u>Given</u><u> </u><u>Information</u><u> </u><u>:</u><u>-</u>

⠀

A polygon with 10 sides ( Decagon )

⠀

<u>To</u><u> </u><u>Find</u><u> </u><u>:</u><u>-</u>

⠀

The value of one of the exterior angles

⠀

<u>Formula</u><u> </u><u>Used</u><u> </u><u>:</u><u>-</u>

⠀

$\qquad \diamond \: \underline{ \boxed{ \pink{ \sf Exterior ~angle = \dfrac {360^\circ}{no. ~of~sides}}}} \: \star$

⠀

<u>Solution</u><u> </u><u>:</u><u>-</u>

⠀

Putting the given values, we get,

⠀

$\sf \dashrightarrow Exterior ~angle = \dfrac{360 ^\circ}{10} \: \: \\ \\ \\ \sf \dashrightarrow Exterior ~angle = \frac{36 \cancel{0}^\circ}{ \cancel{10}} \: \: \\ \\ \\ \sf \dashrightarrow Exterior ~angle = \underline{ \boxed{ \frak{ \red{36^\circ}}}} \: \star \\ \\$

Thus, the value of the exterior angles of a Decagon is 36°.

⠀

$\underline{ \rule{227pt}{2pt}} \\ \\$

8 0

2 years ago

Read 2 more answers

In which section of the number line is √5?

Ymorist [56]

We know that $\sqrt(4)$ and $\sqrt(9)$ are 2 and 3 respectively. Therefore, $/sqrt(5)$ is between 2 and 3, approximately 2.2.

6 0

3 years ago

What is the range of the relation?

Bas_tet [7]

They are on quarenent one

7 0

3 years ago

Write an equation of a line in slope intercept form that is parallel to the line x + 4y = 6 and passes through (-8, 5).

Kisachek [45]

Let us find the slope of the line : x+ 4y = 6

we can write it as 4y = -x +6

y = -(1/4) x + ( 6/4)

slope of the line y= mx + b is m

so here slope = m = -1/4

because we have to find a paraller line so the slope for required line would be same : -1/4

equation of the line having slope m and passing through x1 y1 is :

Y= m( X-x1) + y1

let's plug m= -1/4 x1= -8 and y1 = 5

Y= (-1/4) ( X- -8) + 5

Y= ( -1/4) ( x+8) + 5

Y= (-1/4)( X ) + (-1/4)( 8) + 5

Y= (-1/4) x + 3

Let us now work on second part :

given line is : 2x- 3y = 12

let's write it -3y = -2x +12

y= (-2/-3) x + ( 12/ -3)

Y= ( 2/3) x - 4

slope of this line is 2/3

the required line is perpendicular to it

so the slope of required line = negative resiprocal of this slope =

(-1/ slope of this line ) = -1/( 2/3) = -3/2

Equation of line with slope m= -3/2 and passing through x1= 2 and y1 = 6 is :

Y= m( X-x1) + y1

Y= ( -3/2) ( X- 2) + 6

Y= (-3/2) X - 2(-3/2) + 6

Y= ( -3/2 ) X + 9

Answer : for part 1 : Y= ( 2/3) x - 4

Answer for part 2 : Y= ( -3/2 ) X + 9

7 0

3 years ago

Read 2 more answers