What is the highest percentage of water vapor that could be in the air hurry help

zlopas [31]

Answer:

6.022 × 10²³ molecules of B₂H₆

Explanation:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

B₂H₆ molecules:

21.63 g = one mole of B₂H₆= 6.022 × 10²³ molecules of B₂H₆

8 0

3 years ago

How many grams of H2 will react with 350 g of N2?

miss Akunina [59]

Answer:

10.80

Explanation:

As per the equation, let us calculate the mole ratio. N2+3H2→2NH3. As per the equation one mole of nitrogen reacts with 1 mol of hydrogen.

In terms of mass. 28.01 g of nitrogen needs 3 mol of hydrogen or 6.048 g of hydrogen.

We can set up the ratio;

28.01 g of

l

N

2

needs

6.048 g of

l

H

2

1 g of

l

N

2

needs

6.048

28.01

g of

l

H

2

50.0 g of

l

N

2

needs

6.048

×

50.0

28.01

l

g of

l

H

2

=

10.80 g of

l

H

2

6 0

3 years ago

Density equals what?

Schach [20]

Answer:

Not exactly sure what you mean by this, but "The average density of an object equals its total mass divided by its total volume."

Explanation:

Hope this helps!

3 0

3 years ago

Read 2 more answers

Consider this hydrocarbon. A hexagon. Is this an aromatic hydrocarbon? Why or why not? Yes, because the carbon chain is made up

grin007 [14]

Answer:

C. No, because the carbon chain is composed of only a single ring.

Polycyclicity, having more than a single ring, is a property of only aromatic hydrocarbons. Therefore, if the hydrocarbon is not polycyclic, it is non-aromatic

Explanation:

Cyclic Hydrocarbons

These are organic compounds which are cyclic in structure. The compound cyclohexane involves a ring of six carbon atoms, each of which is also bonded to two hydrogen atoms

Aromatic hydrocarbons are cyclic ring organic compound which are based on the benzene ring structure.

A. If the hexagon contains single bonds, it is non-aromatic.

B. No. Having a ring shape does not on its own determine the aromaticity of a hydrocarbon.

C. Polycyclicity, having more than a single ring, is a property of only aromatic hydrocarbons. Therefore, if the hydrocarbon is not polycyclic, it is non-aromatic

D. Having double bonds within a ring is not a criteria for being aromatic. Both aromatic and non-aromatic hydrocarbons have double bonds within their rings. However, aromatic hydrocarbons have alternate double and single bonds within their 6-carbon ring structure.

Note: Since the structure of the required hydrocarbon is not shown, the explanation contains attachments of hexagonal structures of three hydrocarbons; one non-aromatic and the other two are aromatic. Cyclohexane is non-aromatic while Benzene and the polycyclic compounds are aromatic.

7 0

3 years ago

A student weighs out a 6.64 g sample of , transfers it to a 500. mL volumetric flask, adds enough water to dissolve it and then

Vsevolod [243]

Answer:

the molarity of cobalt(II) fluoride in the resulting solution is = 0.137 M

Explanation:

Given that :

a student dissolves 6.64 g of CoF₂ into 500 mL of water

volume of the solution(water) = 500 mL = 0.50 L

The standard molar mass of CoF₂ is 96.93 g/mol

number of moles of CoF₂ = mass of CoF₂/molar mass of CoF₂

number of moles of CoF₂ = 6.64 g/96.93 g/mol

number of moles of CoF₂ = 0.0685 mol

The molarity of any given substance is known to be as the number of moles of solute dissolved in one litre of solution.

Thus ;

Molarity of cobalt(II) fluoride CoF₂ in the resulting solution is = number of moles / Volume in (L)

Molarity of cobalt(II) fluoride CoF₂ = 0.0685 mol/ 0.50 L

= 0.137 M

Thus ; the molarity of cobalt(II) fluoride in the resulting solution is = 0.137 M

7 0

3 years ago