Answer : The ratio of effusion rates for helium and argon is 3.2 : 1
Solution : Given,
Molar mass of Helium = 4 g/mole
Molar mass of Argon = 40 g/mole
Rate of effusion : It is defined as the rate of effusion of a gas is inversely proportional to the square root of the molar mass of the gas.
Formula used :
where, M is the molar mass.
Now put all the given values in this expression, we get
Therefore, the ratio of effusion rates for helium and argon is 3.2 : 1
1°/ . 2 Al + 6 HCl → 2 AlCl3 + 3 H2
<span>k1 = n(Al) / 2 = 4,5 / 2 = 2,25 </span>
<span>k2 = n(HCl) / 6 = 11,5 / 6= 1,92 </span>
<span>k2 < k1 ==> HCl is the limiting reactant </span>
<span>6 mol of HCl ---> 2 mol of H2 </span>
<span>11,5 mol of HCl ---> 3,83 mol of H2 </span>
Answer:
0.1gmin-1
Explanation:
mass = 0.5g
time = 5minutes
rate= mass/time = 0.1gmin-1
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Answer:
A. 2.44g
B. Kd = 3.2
Explanation:
Concentration of benzoic acid = 50mL = 0.05L
Molecular weight = 122 g/mol
Moles of benzoic acid before the extraction = mass/molecular weight of Benzoic acid
= molar concentration * volume
Moles of benzoic acid before the extraction = 0.05 * 0.4
= 0.02moles of benzoic acid before extraction.
Mass of benzoic acid = 0.02 * 122
= 2.44 g
Partition coefficient, Kd is defined as the ratio of concentration of a substance in an organic medium to the concentration of the substance in the aqueous medium.
Since 1.22g of Benzoic acid was in Dicholoroethane, therefore (2.44 - 1.22)g of benzoic acid was in water.
Mass concentration of benzoic acid in water = mass of benzoic in water/volume of water
= 1.22/0.05
= 24.4 g/L
Mass concentration of benzoic acid in Dicholoroethane = mass of benzoic in Dicholoroethane/volume of Dicholoroethane
= 1.22/0.03
= 40.67g/L
Kd = [concentration]organic/[concentration]aqueous
= 40.66/24.4
= 1.67
