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Ilya [14]
3 years ago
6

HELP FASTTT

Chemistry
1 answer:
3241004551 [841]3 years ago
6 0

Explanation:

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wish you the best on this assignment love, god bless you my dear .

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Calculate molecules in 1dm^3 of oxygen
Archy [21]

Number of molecules in 1 dm³ Oxygen = 2.71 x 10²²

<h3>Further explanation</h3>

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³

1 dm³ of oxygen = 1 L Oxygen

  • mol Oxygen :

\tt \dfrac{1}{22.4}=0.045`mol

  • molecules of Oxygen :

n=mol=0.045

No = 6.02.10²³

\tt N=n\times No\\\\N=0.045\times 6.02\times 10^{23}\\\\N=2.71\times 10^{22}

5 0
3 years ago
Help plz already know 1&amp;2
Aleonysh [2.5K]
3. A
4. B
5. A
6. E
7. A
8. C
9. A
10. B
Some of these were guesses but they were educated guesses. Best of luck. If some of them are wrong I am sorry.  <span />
3 0
3 years ago
ANSWER FOR BRAINLYEST
Olenka [21]
Is there something else that goes along with this?
6 0
3 years ago
Read 2 more answers
Which side of the electromagnetic spectrum has shorter wavelengths
kondaur [170]

Answer:blue blue blue

Explanation:

Just answered it and got it right

7 0
3 years ago
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H2(g) + CO2(g) + 10 kcal H2O(g) + CO(g)
EleoNora [17]

<u>Answer:</u> The equilibrium constant for the given reaction is 0.8

<u>Explanation:</u>

Equilibrium constant is defined as the ratio of concentration of the products raised to the power its stoichiometric coefficients to the concentration of reactants raised to power its stoichiometric coefficient. It is represented as K_c

For the general equation:

aA+bB\rightleftharpoons cC+dD

The equilibrium constant is represented as:

K_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}

For the given chemical equation:

H_2(g)+CO_2(g)+10 kcal\rightleftharpoons H_2O(g)+CO(g)

K_c for this equation is given by:

K_c=\frac{[H_2O][CO]}{[H_2][CO_2]}

Concentration at equilibrium of

H_2=2mol/L\\H_2O=4mol/L\\CO_2=5mol/L\\CO=4mol/L

Putting values in above equation, we get:

K_c=\frac{4\times 4}{2\times 5}\\K_c=0.8

Hence, the equilibrium constant for the given chemical reaction is 0.8

6 0
3 years ago
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