If the hydrogen ion concentration of an unknown solution is 4.56E-7, the pH of the solution will be 6.34 and it will form an acid.
<h3>How to calculate pH from H+?</h3>
The pH, which is the power of hydrogen, can be calculated from the hydrogen ion concentration using the following expression:
pH = - log [H+]
According to this question, the hydrogen ion concentration of an unknown solution is 4.56E-7. The pH is as follows:
pH = - log [4.56E-7]
pH = 6.34
Therefore, If the hydrogen ion concentration of an unknown solution is 4.56E-7, the pH of the solution will be 6.34 and it will form an acid.
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Answer: <u><em>Hope this helps</em></u>
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Explanation:</h3><h3>
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Answer:
not aromatic
Explanation:
Cyclopropene -
as the compound is is made to lose a proton , and gains a negative charge on its ring ,
Now, The ring can become aromatic or anti - aromatic depending on the number of π electrobns ,
According to Huckel 's rule ,
The cyclic compounds with ( 4n+2 ) π electrons , where , n = 0, 1, 2, 3 ... , are considered to be aromatic in nature ,
And the cyclic compounds with ( 4n ) π electrons , where , n = 1, 2, 3 ... , are considered to be anti - aromatic in nature.
Now, for the cyclopropene structure , the number of π electron are equal to 4 , 2 from the double bond and 2 from the negative charge .
Therefore , the compound becomes not aromatic or anti - aromatic .
Answer:
2.29 m.
Explanation:
The following data were obtained from the question:
Mass of KOH = 42.3 g
Molar mass of KOH = 56.11 g/mol
Mass of water = 329 g
Molality of KOH = ?
Next, we shall determine the number of mole in 42.3 g of KOH. This can be obtained as follow:
Mass of KOH = 42.3 g
Molar mass of KOH = 56.11 g/mol
Mole of KOH =?
Mole = mass /Molar mass
Mole of KOH = 42.3/56.11
Mole of KOH = 0.754 mole
Next, we shall convert 329 g of water to kilogram (kg). This can be obtained as follow:
1000 g = 1 kg
Therefore,
329 g = 329 g /1000 g × 1 kg
329 g = 0.329 kg
Therefore, 329 g of water is equivalent to 0.329 kg
Finally, we shall determine the molality of the KOH solution ad follow:
Molality is defined as the mole of solute per unit kilogram of solvent (water) i.e
Molality = mole/ mass (kg) of water
Mole of KOH = 0.754 mole.
Mass of water = 0.329 kg.
Molality = mole/ mass (kg) of water
Molality = 0.754/0.329
Molality = 2.29 m
Therefore, the molality of the KOH solution is 2.29 m.
