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Svetach [21]
3 years ago
11

How do you find the AOS and vertex of a quadratic?

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
3 0

Answer:

The standard form of a quadratic is y = ax^2 + bx + c.

  • In this equation, the formula for the axis of symmetry is x = \frac{-b}{2a}.
  • You know that the center will always be along that line, and you've got the x-coordinate already, so just plug that in and get the y-coordinate out for the center.

The vertex form of a quadratic is also helpful, y = a(x-h)^2 + k.

  • In this equation, the formula for the center is (h, k), and the axis of symmetry is x = h! That's even easier!
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So I tried everything I could but I still don’t know
Effectus [21]

Step-by-step explanation:

app it's a standard 30 60 90 triangle. there are rules for this.

x = 3

y = 6

6 0
3 years ago
G(a)=33a−2; Find g(1)
Pepsi [2]

g(a)=33a−2; Find g(1)

g(1) means the value of a is 1. Replace a in the equation with 1 and solve.

33(1) - 2 = 33-2 = 31

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Log8(216)+[log(42)_log(6)]÷log(49)​
makkiz [27]

Answer:

  • 3 log (3) + 1/2

Step-by-step explanation:

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7 0
3 years ago
How can you tell from the scale factor whether the original figure was enlarged or reduced?
Stels [109]

If the scale factor is less then 1, it was reduced.

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8 0
3 years ago
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Solve the following equation for x: 5x + 3y = 15.
zepelin [54]

Answer:

B) x = (-3/5)y + 3

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

first, subtract 3y from btoh sides:

5x + 3y (-3y) = 15 (-3y)

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Next, divide 5 from both sides:

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x = (-3/5)y + 3

B) x = (-3/5)y + 3 is your answer.

~

8 0
3 years ago
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