Answer:
68
Step-by-step explanation:
40+28
Answer:
6250
Step-by-step explanation:
Fill in the given number and solve for x. The answer is 1000x, rounded.

x is in thousands, so 6.25×1000 = 6,250 passengers flew in June.
Answer:
A.) (x + 2) and (2x - 1)
Step-by-step explanation:
So from the video i just watch this is how its done
3 (2x^2 + 3x - 2) = 0
4 and -1 gives you 3 and you divide them by a which is 2
4/2 (2/1) and -1/2 then you write them from the bottom to top
(x + 2) and (2x - 1)
Answer:
B.) 20 (x + 5) (x - 5) = 0
Step-by-step explanation:
20 (x^2 - 25) = 0
20 (x + 5) (x - 5) = 0
EZ
Answer:

And the width for the confidence interval is given by:

And we want to see the effect if we increase the confidence level for a interval. On this case if we increase the confidence level then the critical value for the confidence interval
would be higher and then the width of the interval would increase. So then the best answer for this case would be:
B. Increasing the level of confidence widens the interval.
Step-by-step explanation:
Let's assume that we have a parameter of interest
who represent for example the true mean for a population. And we can construct a confidence interval in order to estimate this parameter if we know the distribution for the statistic let's say
and for this particular example the confidence interval is given by:

Where ME represent the margin of error for the estimation and this margin of error is given by:

And the width for the confidence interval is given by:

And we want to see the effect if we increase the confidence level for a interval. On this case if we increase the confidence level then the critical value for the confidence interval
would be higher and then the width of the interval would increase. So then the best answer for this case would be:
B. Increasing the level of confidence widens the interval.
For this question you should know that 2/3 is equal to 20/30 so now you can see that 21/30 is greater than 20/30 :)))
i hope this is helpful
have a nice day