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nalin [4]
4 years ago
6

Predict how decreasing the volume of the container used for the reaxtion below affect the initial rate of the reaction and expla

in your prediction.
H2(gas) + I2(gas) ---> HI2
Chemistry
1 answer:
77julia77 [94]4 years ago
3 0
Decreasing the volume increases the pressure, therefore due to Le Chatelier's principle, we can see that more HI2 will be formed as 2 molecules combine into 1 and that conserves space which in turn lowers the pressure.
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The orbit closest to the nucleus has ___________ energy.
deff fn [24]

Answer:

inonic bonds with cavalent bonds

Explanation:

ionic bonds

5 0
3 years ago
N2(g) + 2 O2(g) → 2 NO2(g)
marshall27 [118]

Answer: 1.057444301e-018

Explanation:

4 0
3 years ago
7. A small roll of double-sided tape is 6.35m long and 1.2 x 102m wide. What is the total area that could be
allsm [11]

The total area that could be covered by this roll of tape is 0.1524 m².

<h3>What is the double-sided tape?</h3>

A double-sided tape is a tape that can be stick from both sides. It is used to stick something on a surface. A rectangle is an object that has four sides in which two sides are equal.

If we unroll the tape, we will see that it is a rectangle with dimensions:

length = 6.35 m

width = 1.2 x 10⁻² m

Since the tape has two sides, the total area of the tape is:

A = 2 x (length x width)

A = 2 x 6.35 x 1.2 x 10⁻²

A = 0.1524 m²

Thus, the total area of the tape is 0.1524 m²

To learn more about the area of rectangle, refer to the link:

brainly.com/question/8663941

#SPJ1

7 0
2 years ago
Calculate the amount in grams of Na2CO3 needed to react with HCL to produce 120g NaCl
worty [1.4K]
Let's start off with the balanced chemical equation:

Na_2CO_{3_{(s)}} + \textbf2HCl_{_{(aq)}}\rightarrow CO_{2_{(g)}} + H_2O_{_{(l)}} + \textbf2NaCl_{_{(aq)}}

Assuming the sodium carbonate is the limiting reagent, look at the coefficients of sodium carbonate and sodium chloride and use those as a ratio of sodium carbonate to sodium chloride: 1:2.

Since you have the required mass of NaCl, convert this to moles.

Assuming you know how to find the molar mass of NaCl:

M_{NaCl} = 58.44g/mol
n = \frac{m}{M}
n_{NaCl} = \frac{120g}{58.44g/mol}
n_{NaCl} = 2.053mol

Using the ratio, since 1 mole of sodium carbonate is required to produce 2 moles of sodium chloride, cross-multiply the ratios:

1:2 = x:2.053mol
2x = 2.053mol
x = 1.027mol

Therefore 1.027 moles of sodium carbonate is required to produce the required amount of sodium chloride. Convert to mass for your final answer:

n_{Na_2CO_3} = 1.027mol
M_{Na_2CO_3} = 105.99g/mol
m = nM
m = (1.027mol)(105.99g/mol)
m_{Na_2CO_3} = 108.85g

Hope this helps :)
6 0
3 years ago
What two particles are found in the nucleus of an atom?
kotegsom [21]

Answer: it has one proton and electron

Explanation:

3 0
3 years ago
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