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2 years ago

10

ernesto tiene 18 metros de malla el desea cerca solo tres lados de un terreno rectangular , ya que una pared sirve de limite del

cuarto lado

2 answers:

Flura [38]2 years ago

6 0

Answer:

Estoy prediendo espanol, as translate.

Step-by-step explanation:

mote1985 [20]2 years ago

6 0

please write the question properly

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A library building is in the shape of a rectangle. Its floor has a length of (3x + 5) meters and a width of (5x − 1) meters. The

malfutka [58]

We can use the Front Outside Inside Last (FOIL) method to expand the double bracket

$(3x+5)(5x-1)$

Front ⇒ $(3x)(5x)=15 x^{2}$
Outside ⇒ $(3x)(-1)=-3x$
Inside ⇒ $(5)(5x)=25x$
Last ⇒ $(5)(-1)=-5$

Put the four terms together we have
$15 x^{2} -3x+25x-5$ , then collect like terms
$15 x^{2} +22x-5$

5 0

3 years ago

Read 2 more answers

Find the derivative of the function at P 0 in the direction of A. f(x,y,z) = 3 e^x cos(yz), P0 (0, 0, 0), A = - i + 2 j + 3k

Alik [6]

The derivative of $f(x,y,z)$ at a point $p_0=(x_0,y_0,z_0)$ in the direction of a vector $\vec a=a_x\,\vec\imath+a_y\,\vec\jmath+a_z\,\vec k$ is

$\nabla f(x_0,y_0,z_0)\cdot\dfrac{\vec a}{\|\vec a\|}$

We have

$f(x,y,z)=3e^x\cos(yz)\implies\nabla f(x,y,z)=3e^x\cos(yz)\,\vec\imath-3ze^x\sin(yz)\,\vec\jmath-3ye^x\sin(yz)\,\vec k$

and

$\vec a=-\vec\imath+2\,\vec\jmath+3\,\vec k\implies\|\vec a\|=\sqrt{(-1)^2+2^2+3^2}=\sqrt{14}$

Then the derivative at $p_0$ in the direction of $\vec a$ is

$3\,\vec\imath\cdot\dfrac{-\vec\imath+2\,\vec\jmath+3\,\vec k}{\sqrt{14}}=-\dfrac3{\sqrt{14}}$

3 0

3 years ago

This Question: 1 pt

zhenek [66]

$\huge{ \mathfrak{ \underline{ Answer }\: \: ✓ }}$

Angles forming linear pair are :

$\mathrm{\angle EFG \: \: and \: \: \angle GFH}$

And we know, they are supplymentary

$\mathrm{\angle EFG \: + \: \angle GFH} = 180 \degree$
$3n +1 9 \degree+ 2n + 36\degree = 180 \degree$
$5n + 55\degree = 180\degree$
$5n = 125\degree$
$n = 25\degree$

So, the measures of the given angles are :

$\mathrm{\angle EFG } = 3n + 19$
$\mathrm{ \angle EFG = (3 \times 25\degree) + 19}$
$\mathrm{ \angle EFG = 75 \degree+ 19\degree}$
$\mathrm{ \angle EFG = 94\degree}$

And

$\mathrm{ \angle GFH = 2n + 36}$
$\mathrm{ \angle GFH = (2 \times 25\degree) + 36\degree}$
$\mathrm{ \angle GFH = 50\degree + 36\degree}$
$\mathrm{ \angle GFH = 86\degree }$

_____________________________

$\mathrm{ ☠ \: TeeNForeveR \:☠ }$

6 0

3 years ago

H has 3 times more balls than K. they have 940 balls in all. How many more balls does H have than k?

Harman [31]

K+ 3k = 940

4k= 940

K= 940/4

K= 235

H= 3k

H= 3×>235 = 705

K= 235

H= 705

Happy to help! Please mark me as the brainliest!

3 0

3 years ago

The legs of a right triangle measure 8 inches and 12 inches. What is the area

motikmotik

Answer:48 sq. Inches

Step-by-step explanation:

8 0

3 years ago