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4 years ago

11

A tornado lifts a truck 252 m above the ground. As the storm continues, the tornado throws the truck horizontally. It lands 560

m away from where it was picked up.
How fast was the truck traveling horizontally through its flight? Round to the nearest tenth.

2 answers:

DochEvi [55]4 years ago

7 0

Answer;

-78.1 m/s

Explanation;

-Vertical component of velocity is parabolic while the Horizontal component is constant.

Initial velocity = 0 , initial height = 252

dy = v0*t + ½at²

dy= vo + 0.5gt^2

252 = 0 + 4.9t^2

t = 7.17 seconds

horizontal:

vx = (dx)/t = (560 m)(7.17 s) = 78.103 m/s

To the nearest tenth; 78.1 M/s

Rama09 [41]4 years ago

6 0

The answer is 78.1 I already checked it

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