Question

A tornado lifts a truck 252 m above the ground. As the storm continues, the tornado throws the truck horizontally. It lands 560 m away from where it was picked up.
How fast was the truck traveling horizontally through its flight? Round to the nearest tenth.

Answer 1

Answer;

-78.1 m/s

Explanation;

-Vertical component of velocity is parabolic while the Horizontal component is constant.

Initial velocity = 0 , initial height = 252

dy = v0*t + ½at²

dy= vo + 0.5gt^2

252 = 0 + 4.9t^2

t = 7.17 seconds

horizontal:

vx = (dx)/t = (560 m)(7.17 s) = 78.103 m/s

To the nearest tenth; 78.1 M/s

Answer 2

The answer is 78.1 I already checked it