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Butoxors [25]
2 years ago
14

In the diagram, q1, q2, and q3 are in a straight line.

Physics
1 answer:
schepotkina [342]2 years ago
3 0

Answer:

did anyone figure it out

Explanation:

please help

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Adding resistors in series changes the total resistance of a circuit by
skelet666 [1.2K]

Answer:

Increasing the resistance

Explanation:

6 0
3 years ago
A copper rod of length 27.5 m has its temperature increases by 35.9 degrees celsius. how much does its length increase?(unit=m)
gavmur [86]
<h2>The increase in length = 1.87 x 10⁻²</h2>

Explanation:

When copper rod is heated , its length increases

The increase in length can be found by the relation

L = L₀ ( 1 + α ΔT )

here L is the increased length and L₀ is the original length

α  is the coefficient of linear expansion and ΔT is the increase in temperature .

The increase in length = L - L₀ = L₀ x α ΔT

Substituting all these value

Increase in length = 27.5 x 1.7 x 10⁻⁵ x 35.9

= 1.87 x 10⁻² m

5 0
3 years ago
Read 2 more answers
How much work is accomplished when a force of 250 N pushes a box across the floor for a distance of 50 meters?
IrinaK [193]
Work = force * distance
and newton*meters = Joule

In this case,  work = 250N*50m = 12500 J

So the answer is D) 12,500 J

3 0
3 years ago
A 0.10 kg mass is oscillating at a small angle from a light string of length 0.10 m.
cupoosta [38]

Answer:

tough

Explanation:

5 0
2 years ago
We want to find how much charge is on the electrons in a nickel coin. Follow this method. A nickel coin has a mass of about 4.2
monitta

Answer:

The number of atoms is N = 4.37*10^{22} \ atoms

Explanation:

From the question we are told that

                 The mass of coin  is m_n = 4.2g

                   Number of atom in one mole = n =6.02*10^{23} \ atoms

                   Molar mass of nickel M = 57.8g

Now the relation to obtain the number of atom in  the  nickel coin is

                        N = \frac{Mass \ of Nickel\ coin}{Molar \ mass\ of nickel }  * No\ of\atoms \ in \ \ one\  mole\ of\ nickel

                           = \frac{4.2}{57.8}* 6.02*10^{23}

                           =4.37 *10^{22} atoms

                 

     

8 0
3 years ago
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