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Sliva [168]
4 years ago
15

Suppose that for a particular hypothesis test, the consequences of a Type I error are not very serious, but there are serious co

nsequences associated with making a Type II error. Would you want to carry out the test using a small significance level α (such as 0.01) or a larger significance level (such as 0.10)? Explain the reason for your choice.
Mathematics
1 answer:
VARVARA [1.3K]4 years ago
5 0

Answer:

We want to reduce type II error we carry out the test using a larger significance level (such as 0.10) and not a small significance level α (such as 0.01).

Step-by-step explanation:

Type I error

  • Rejecting the null hypothesis when it is in fact true is called a Type I error.
  • It is denoted by alpha, α that is the significance level.
  • Lower values of alpha make it harder to reject the null hypothesis, so choosing lower values for alpha can reduce the probability of a Type I error.

It is given that the consequences of a Type I error are not very serious, but there are serious consequences associated with making a Type II error.

Type II error

  • This is the error when we fail to reject a false null hypothesis or accept a null hypothesis when it is true.
  • Higher values of alpha makes it easier to reject the null hypothesis.
  • So choosing higher values for alpha can reduce the probability of a type II error.
  • The consequence here is that if the null hypothesis is true, increasing the value of alpha makes it more likely that we make a Type I error.

Since, we want to reduce type II error we carry out the test using a larger significance level (such as 0.10) and not a small significance level α (such as 0.01).

This will increase type I error but that is okay since we do not have serious consequences for it.

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OK so here it goes:
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3a) 0.02, 0.2, 2, 20, 200, 2000
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6 0
3 years ago
What is the length of side BC of the triangle? Enter your answer in the box.
kondor19780726 [428]

The triangle is an equiangular triangle so that means it must be an equilateral triangle.

3x - 3 = x + 8

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7 0
4 years ago
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AleksAgata [21]

Answer:

f^{-1}(x) = 4x-3 is the right answer.

Step-by-step explanation:

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f(x)=\frac{1}{4}(x+3)

Then we have to find inverse of function f(x).

we will write the equation as y=\frac{1}{4}(x+3)

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x = 4y - 3

Now we will rewrite the function as

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4 years ago
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I need this to be simplified
umka2103 [35]

Answer:

\frac{x+2}{3x-1}

Explanation:

→ \frac{(x^2-9)(x+2)}{(3x^2 +8x -3)(x-3)}

→ \frac{\left(x+3\right)\left(x-3\right)\left(x+2\right)}{\left(3x^2+8x-3\right)\left(x-3\right)}

→ \frac{\left(x+3\right)\left(x+2\right)}{3x^2+8x-3}

→ \frac{\left(x+3\right)\left(x+2\right)}{\left(3x-1\right)\left(x+3\right)}

→ \frac{x+2}{3x-1}

8 0
2 years ago
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