Given:
Reflect square JKLM with J(1, 4), K(6, 5), L(7, 0) and M(2, -1) in the y-axis.
To find:
The coordinates of M'.
Solution:
We have, M(2, -1) .
If a figure reflected over the y-axis then

Using this rule, we get

Therefore, the coordinates of point M' are (-2,-1).
Answer:
D -2/5
Step-by-step explanation:
So first you count up or down from a point, that's 2
then you'll count side to side that's 5
2/5
but this is a negative slope because it's pointing up to the left
-2/5 is the slope
Answer:
B -3.
Step-by-step explanation:
The slope = (y2-y1)/(x2-x1)
= (-2-4)/(8-6)
= -6/2
= -3.
Following PEDMAS it'd be
=0
0+(50x1)-60-(60x0)+10
0+50-60-0+10
50-60+10
-10+10=0
Hope this helps. :)
2b-16>12 add the 16 2b>28 then divide by 2
b>14