Answer:
Step-by-step explanation:
radius r = 5 cm
Height h = 5 cm
Volume of cylinder = πr²h
= π * 5 * 5 * 5
= 125π cm³
It's b 240000
I'm sorry if wrong I'm not too good at these things
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
P(brown) = 12% = 0.12
P(Yellow) = 15% = 0.15
P(Red) = 12% = 0.12
P(blue) = 23% = 0.23
P(orange) = 23% = 0.23
P(green) = 15% = 0.15
A.) Compute the probability that a randomly selected peanut M&M is not yellow.
P(not yellow) = P(Yellow)' = 1 - P(Yellow) = 1 - 0.15 = 0.85
B.) Compute the probability that a randomly selected peanut M&M is brown or red.
P(Brown) or P(Red) :
0.12 + 0.12 = 0.24
C.) Compute the probability that three randomly selected peanut M&M’s are all brown.
P(brown) * P(brown) * P(brown)
0.12 * 0.12 * 0.12 =0.001728
D.) If you randomly select three peanut M&M’s, compute that probability that none of them are blue.
P(3 blue)' = 1 - P(3 blue)
P(3 blue) = 0.23 * 0.23 * 0.23 = 0.012167
1 - P(3 blue) = 1 - 0.012167 = 0.987833
If you randomly select three peanut M&M’s, compute that probability that at least one of them is blue.
P(1 blue) + p(2 blue) + p(3 blue)
(0.23) + (0.23*0.23) + (0.23*0.23*0.23)
0.23 + 0.0529 + 0.012167
= 0.295067
So first let’s put g(f(x)) together by putting f(x) for every x in g(x)
We get g(f(x))=3(3/4x+3)+4 which is the selling price equation
Then you plug in 20 to find the selling price for 20 muffins.
g(f(x))=3(3/4(20)+3)+4
g(f(x))=3(60/4+3)+4
g(f(x))=3(18)+4
g(f(x))=54+4
g(f(x))=58
So the selling price will be $58 for 20 muffins.
Answer:
113
Step-by-step explanation:
Let the number of adult tickets sold =a
Let the number of student tickets sold =s
A total of 259 tickets were sold, therefore:
a+s=259
Adult tickets were sold for $24 each and student tickets were sold for $16 each.
Total Revenue = $5,312
Therefore:
24a+16s=5,312
We solve the two derived equations simultaneously.
From the first equation
a=259-s
Substitute a=259-s into 24a+16s=5,312
24(259-s)+16s=5,312
6216-24s+16s=5,312
-8s=5,312-6216
-8s=-904
Divide both sides by -8
s=113
Therefore, 113 student tickets were sold.
