If x and y are integers, and 3x + 2y = 13, which of the following could be the value of y ?

Mathematics

2 answers:

fiasKO [112]3 years ago

8 0

C. 2
Because
3x+2(2)=13
3x+4=13
3x=9
x=3

None of the other solutions work out so that both x and y are integers.

lions [1.4K]3 years ago

3 0

They are all integers so...
first lets substitute
A.3x=13
X=13/3
b.3x+2=13
3x=11
x=11/3
c.3x+4=13
3x=9
x=3
d.3x+6=13
3x=7
x=7/3

E.3x+8=13
3x=5
x=5/3

therefore the possible is letter c because it must be an integer and the definition of integer states that it is not a decimal nor a fraction

You might be interested in

What is the slope of the line conaning the points (-3,4)and(2,1)

olya-2409 [2.1K]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ -3 &,& 4~) 
% (c,d)
&&(~ 2 &,& 1~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-4}{2-(-3)}\implies \cfrac{1-4}{2+3}\implies \cfrac{-3}{5}$

4 0

3 years ago

What is f (x) = 4x + 1; {–4, –2, 0, 2, 4}

Reika [66]

Answer

4x+1

−4,−2,0,2,4

Step-by-step explanation:

5 0

2 years ago

Find the formula for the area of the shaded region in the figure.<br> x² = 4py<br> ہے

Alexandra [31]

The formula for the area of the shaded region in the figure.

x² = 4py is mathematically given as

$A=\frac{8}{3} \sqrt{p h} \cdot h$

<h3>What is the formula for the area of the shaded region in the figure?</h3>

Parameters

$x^{2}=4 p y$

$y=h$

$\therefore x^{2}=4 p h \Rightarrow x=2 \sqrt{p h} \\$

Generally, the equation for the Area is mathematically given as

$& A=2 \int_{0}^{2 \sqrt{p h}}\left(h-\frac{x^{2}}{4 p}\right) d x \\\\& A=2\left(h x-\frac{x^{3}}{12 p}\right]_{0}^{2 \sqrt{p h}} \\\\& A=2\left[\left[h 2 \sqrt{p h}-\frac{1}{12 p} \cdot(2 \sqrt{p h})^{3}-0\right]\right. \\$

$&A=2\left[2 h^{3 / 2} \sqrt{p}-\frac{8(\sqrt{p})^{3}(\sqrt{h})^{3}}{12 p}-0\right] \\\\&A=2\left[2 h^{k / 2} \sqrt{p}-\frac{2}{3} \sqrt{p} \cdot h^{3 / 2}\right] \\\\&A=2 \times \frac{4 \sqrt{p} \cdot h^{3 / 2}}{3} \\\\&A=\frac{8}{3} \cdot \sqrt{p} \cdot \sqrt{h} \cdot h \\\\&A=\frac{8}{3} \sqrt{p h} \cdot h$

$A=\frac{8}{3} \sqrt{p h} \cdot h$

In conclusion, the equation for the Area is

$A=\frac{8}{3} \sqrt{p h} \cdot h$