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3 years ago

What is the length of the side of a right triangle that has a side length of 12in and a hypotenuse that measures 15ft

Mathematics

2 answers:

Viktor [21]3 years ago

7 0

Answer: 14.96ft

Step-by-step explanation:

1. To solve this exercise you must apply the Pythagorean Theorem, which is:

$a=\sqrt{b^{2}+c^{2}}$

Where $a$ is the hypotenuse, and $b$ and $c$ are the other sides of the triangle.

2. You have that the sides given measures 12 inches. 1 feet has 12 inches. Therefore, this side measures 1 feet.

2. Then, when you solve for one of the sides and substitute the values given in the problem into the formula shown above, you obtain that the length of the side of the rigth triangle is:

$b=\sqrt{(15ft)^{2}-(1ft)^{2}}$

$b=4\sqrt{14}=14.96ft$

kati45 [8]3 years ago

4 0

Answer:

14.97 ft

Step-by-step explanation:

We have a right angled triangle with a side length of 12 inches and hypotenuse of 15ft.

To find the other side length, we will use the Pythagoras Theorem but before that, we need to make the units same for both the given sides.

Since 1 feet has 12 inches so we can use both the sides in ft to find the third side length.

$a = \sqrt{b^2+c^2}$

where c is the hypotenuse and a and b are the rest of the sides of the triangle.

$b = \sqrt{(15)^2-(1)^2}$

$b = \sqrt{224}$

$b = 14.97$

Therefore, the third side length is 14.97 ft.

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Margo brought 7 pens from a book store some pens cost $3.00 EACH and the rest cost $4.00 . If she paid a total of 23.00 for the

Montano1993 [528]

Answer:

Step-by-step explanation:

Margo bought 7 pens for $23.

Some pens are $3 and some $4.

We need to find how many $3 pens she bought.

Let the number of $3 pens be represented by p and let the number of $3 pens be represented by r. So:

p = $3 and r = $4

Now we know 7 pens were purchased so is we add the number of $3 pens purchased to the number of $4 pens purchased, we will get 7.

p + r = 7

We know that the total cost of the pens is $23 so that equation would be found by takign the $3 pen multiplied by the number of $3 pens purchsed added to the $4 pen multiplied by the number of $4 pens purchsed, which equals $23.

$3p + $4r = $23

Now we have 2 equations and 2 unknowns.

p + r = 7

$3p + $4r = $23

Let's solve for r in the first equation.

p + r = 7 Subtract p from both sides.

p - p + r = 7 - p The p on the left cancels.

r = 7 - p

Now that we know r, we can substitute it into the second equation and solve for p.

$3p + $4r = $23

3p + 4( 7 - p) = 23 Multiply it out.

3p + 4*7 - 4*p = $23

3p + 28 - 4p = 23 Combine like terms.

3p - 4p + 28 = 23

- 1p + 28 = 23 Subtract 28 from both sides.

- p + 28 - 28 = 23 - 28

- p = - 5 Divide each side by -1

- p/- 1 = - 5/ - 1 The negative cancels on each side.

p = 5

We can see Margo bought 5 $3 pens.

For fun, let's solve for how many $4 pens she bought. We know p, so we plug it in the first equation and solve for r.

p + r = 7

5 + r = 7 Subtract 5 from each side

5 - 5 + r = 7 - 5

r = 7 - 5

r = 2

So Margo bought 5 $3 pens and 2 $4 pens!

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Answer:

Yes, it is. Functions can only have one output (y) for each input (x). Furthermore, this means each x value will only have one y passing through it. Thus if we plot it on a graph and it passes through a horizontal line more than once, it is not a function. This is called the vertical line test.

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The population of a certain geographic region is approximately 103 million and grows continuously at a relative growth rate of 1

aev [14]

The population increases by a factor 1.0167 every year so the require figure is:
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