Answer:
D
Step-by-step explanation:
As you can see, the range of the graph is all real numbers greater than -4. Therefore you can tell that -4 will have to be in the equation leaving only options B and D. When graphing B and D, D fits the image.
Answer:
6) x=9.75
10) Triangle OMN ~ Triangle ODK; SSS ~
11) SSS ~ theorem
12) SSS ~ theorem
Step-by-step explanation:
For #6, since the polygons are similar, then it must mean AD is congruent to JM and CD is congruent to LM. Now we can set up the proportion 39/20=x/5 and solve. Solving for x gets us x=9.75, so C is the correct choice
For #10, there's no information about angles whatsoever in the diagram, so B and C must be wrong. D must be wrong as well because if the triangles weren't similar, then why is OJ ~ JM and OK ~ KN? So thus, the triangles are similar by SSS.
For #11, this is sort of a no-brainer because there's no mention of angles, so D must be correct.
For #12, same concept, no mention of angles, all sides are similar to their respective sides of the different triangles, so A is correct.
Answer:
2.3 units
Step-by-step explanation:
The unknown side is opposite the given angle 50 degrees, and the length of the hypotenuse is 3 units.
Since sin Ф = opp / hyp, we have here sin 50° = x/3, or x = 3 sin 50°.
Using a calculator, we find that the sine of 50° is 0.776.
Therefore, x = 3(0.766) = 2.298 units, or approximately 2.3 units
If I'm doing this right, I'm pretty sure the answer would be 7, since 0 + 1 = 1, 8 - 1 = 7, and 7 x 1 = 7.
I hope this answer helped you! If you have any further questions or concerns, feel free to ask! :)
Answer:
1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.
Step-by-step explanation:
The order in which the teachers are chosen is not important, which means that the combinations formula is used to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
In this question:
1 from a set of 2(Either Mrs. Vera or Mr. Jan).
3 from a set of 18 - 2 = 16. So
1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.
