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Gemiola [76]
3 years ago
11

In a biological lab, the cell growth rate of two different organisms is tracked and recorded each week. Given the growth rate, t

he number of organisms can be determined using the following equations:
s(x) = 100 + 23x
m(x) = 90(1.2x)

Complete the table of values.
x 100 + 23x 90(1.2x)
0
1
2
3
4
5
Use the table to determine at approximately which point the number of cells will be the same for each organism.
Graph the system of equations, and show the point of intersection.
Explain what the points graphed for each line represent.
Explain how you can determine the solution to the equation 100 + 23x = 90(1.2x) using the graph from part c.
Find the point(s) of intersection, and explain what the intersection represents in the context of the problem.
Mathematics
2 answers:
Alenkinab [10]3 years ago
8 0
Wow that's too much work!!! is this a table or printout?

Airida [17]3 years ago
4 0

s(x) = 100 + 23xs(x) = 100 + 23x

m(x) = 90(1.2x)



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<em>answer:</em>

<h3><em>Total </em><em>surface </em><em>area </em><em>of </em><em>3</em><em> </em><em>tanks=</em><em>3</em><em>4</em><em>.</em><em>3</em><em> </em><em>m^</em><em>2</em></h3><h3><em>7</em><em> </em><em>tins </em><em>of </em><em>paint </em><em>are </em><em>required</em><em>.</em></h3>

<em>Solution</em><em>,</em>

<em>diameter </em><em>of </em><em>tank=</em><em>1</em><em>.</em><em>4</em><em> </em><em>m</em>

<em>Height </em><em>of </em><em>tank=</em><em>1</em><em>.</em><em>9</em><em> </em><em>m</em>

<em>Given </em><em>tank </em><em>has </em><em>top </em><em>and </em><em>bottom </em>

<em>Now,</em><em> </em><em>The </em><em>total </em><em>surface </em><em>area </em><em>of </em><em>cylinder </em><em>tank </em><em>is </em><em>given </em><em>by:</em>

<em>tsa = 2\pi \:  {r}^{2}  + (2\pi \: r \: ) \times h</em>

<em>r(</em><em> </em><em>radius </em><em>of </em><em>tank)</em><em>=</em>

<em>\frac{diameter}{2}  =  \frac{1.4}{2}  = 0.7 \: m</em>

<em>h(</em><em>height </em><em>of </em><em>tank)</em><em>=</em><em>1</em><em>.</em><em>9</em><em> </em><em>m</em>

<em>TSA </em><em>of </em><em>1</em><em> </em><em>tank</em>

<em>=</em>

<em>2 \times 3.14 \times  {(0.7)}^{2}  + 2 \times 3.14 \times 0.7 \times 1.9 \\  = 11.435 \:  {m}^{2}</em>

<em>TSA </em><em>Of </em><em>3</em><em> </em><em>tanks</em>

<em>=</em>

<em>3 \times 11.435 \:  {m}^{2}  \\  = 34.3 \:  {m}^{2}</em>

<em>Given </em><em>a </em><em>tin </em><em>of </em><em>plate </em><em>covers </em><em>5</em><em>m</em><em>^</em><em>2</em><em> </em><em>area.</em>

<em>No.of </em><em>tins </em><em>required:</em>

<em>1</em><em> </em><em>tin</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>5</em><em>m</em><em>^</em><em>2</em>

<em>x </em><em>tin</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>3</em><em>4</em><em>.</em><em>3</em><em> </em><em>m^</em><em>2</em>

<em>5x = 34.3(cross \: multiplication) \\ or \: x =  \frac{34.3}{5}  \\ x = 6.86 \\ x = 7 \: tins</em>

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<em>Hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>

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q = 1 - p = 1 - 0.42 = 0.58

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x = 24

Since, the sample size is fixed, the selections are independent and probability of success is constant, we can use the Binomial Probability to answer this problem. All the conditions of a Binomial Distribution are being satisfied.

According to the formula of Binomial Distribution, the probability of getting exactly x success among n trials is given as:

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Using the values, we get:

P(X = 24) =^{30}C_{24}(0.42)^{24}(0.58)^{6}= 0.00002

Thus, the probability of getting exactly 24 consumers from a sample of 30 who are comfortable with drones is 0.00002, which is extremely small.

Since, the value of probability is a very small positive number, it indicates that event is possible but very unlikely. An impossible event has probability equal to 0.

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