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son4ous [18]
2 years ago
7

Write the complex number in polar form with argument between 0 and 2.

Mathematics
1 answer:
pychu [463]2 years ago
5 0

<em>Lets say that √(3+i) is the magnitude of your vector. In polar form, i represents the x component and j represents the y component of the vector. Therefore, the polar form is icosθ√(3+i) + jsinθ√(3+i)</em>

draw a diagram :

<em>z = r(cos θ + i sin θ), where z = complex number, r = modulus, θ = angle of rotation For the given:r = 2θ = π/6 √3 + i = 2(cos π/6 + i sin π/6)</em>

<em>hope</em><em> </em><em>thz</em><em> </em><em>hlpz</em><em> </em><em>✿</em>

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Please answer this question now
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Answer:

<h2>S = 11.4</h2>

Step-by-step explanation:

To find s we use the cosine rule

That's

s² = SU² + ST² - 2(SU)(ST) cos S

From the question

SU = 5

ST = 13

S = 60°

Substituting the values into the expression we have

s² = 5² + 13² - 2(5)(13) cos 60

s² = 25 + 169 - 130cos 60

s² = 194 - 65

s² = 129

Find the square root of both sides

s= √129

s = 11.357816

We have the final answer as

<h3>s = 11.4 to the nearest tenth</h3>

Hope this helps you

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Step-by-step explanation:

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