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3 years ago

How many solutions 4x+3x-8=14+7

Mathematics

1 answer:

grin007 [14]3 years ago

6 0

Answer: 29/7 or 4 1/7

Step-by-step explanation:

4x+3x-8=14+7

7x-8=14+7

7x-8=21

7x=29

x=29/7 or 4 1/7

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Find the value of x. Round to the nearest tenth. Help please!!!

jasenka [17]

Answer:

x=3

Step-by-step explanation:

Right triangle so you can use pythagorean theorem

a squared + b squared = c squared

b=x

14^2 + b^2= 17^2

14+b=17

b=3

8 0

3 years ago

Read 2 more answers

Please! Solve f(x)-g(x) if f(x)=1/2x^4 - x^2 and g(x)= 3/4x^4 +3x^3 - x^2

igomit [66]

Answer:

$f(x)-g(x)=\frac{-1}{4}x^{4}-3x^{3}$

Step-by-step explanation:

This is a subtraction between polynomials, since both functions are polynomials, hence, to solve the problem with need to perform the subtraction, by coefficients.

$f(x)= \frac{1}{2}x^{4}+0x^{3}-x^{2}\\\\g(x)=\frac{3}{4}x^{4}+3x^{3}-x^{2}$

By performing the subtraction, we have:

$f(x)-g(x)=\frac{-1}{4}x^{4}-3x^{3}$

6 0

3 years ago

What is the graph of the equation 9x^2 + 4y^2 - 18x + 8y - 23 = 0 ? Also, how did you get that?

Dmitriy789 [7]

13xy^2-10xy-23=0

you first add the like terms and rewrite and thats how you get the answer

8 0

3 years ago

Which represents the reflection of f(x)=sqrt x over the y axis

zloy xaker [14]

reflection of $f(x)=\sqrt{x}$ over the y axis we get $g(x)=\sqrt{-x}$

Step-by-step explanation:

We need to find the reflection of f(x)=sqrt x over the y axis

So, reflection over y- axis

If the function f(x) is transformed over y-axis then the new function g(x) will be $g(x)= f(-x)$

So, finding reflection of $f(x)=\sqrt{x}$ over the y axis we get:

$g(x)=\sqrt{-x}$

So, reflection of $f(x)=\sqrt{x}$ over the y axis we get $g(x)=\sqrt{-x}$

Keywords: Transformations

Learn more about Transformations at:

#learnwithBrainly

6 0

4 years ago

Hi please help , With solution if it's ok

Snowcat [4.5K]

Answers with Method:-

1) Multiply the length value by 100,000.

$2.5 \: hm = 2.5 \times 100000$

$= >2.5 \: hm = 250000 \: mm$

2) For this, divide the length value by 1000.

$= > \frac{1800}{1000}$

$= > 1.8 \: dam$

3) For finding the approximate value, just multiply the value of length by 1.609.

$= >6450 \: m = (6450 \times 1.609) \: km$

$= > 10380.27 \: km$

4) Multiply the given mass value by 100.

$= > 1.2 \: kg = 1.2 \times 100$

$= > 1200 \: g$

5) Multiply the given value by 10,000.

$4.37 \: dag = 4.37 \times 10000$

$= > 43700 \: mg$

5 0

3 years ago